3.13
cot 115 deg = - tan25 deg
22 % grade: go horizontally 100, go vertically 22, hypotonuse is slope. angle is INV tan ( 22 / 100 ) = 12.407 degrees from horizontal
tan (30 degrees) would be equal to 0.577350269.
If B is 90 degrees, Tan A is BC / AB. But I don't know what you mean by Tan A by 2.
0.813
The cotangent function is the reciprocal of the tangent function, so cot(115 degrees) is equivalent to 1/tan(115 degrees). Since tan(115 degrees) is equivalent to -tan(65 degrees) due to the periodicity of the tangent function, cot(115 degrees) simplifies to -tan(65 degrees), which corresponds to option A.
cot 115 deg = - tan25 deg
Tan 42 degrees = 0.9004
Tan(74 degrees) = 3.487414444.....
22 % grade: go horizontally 100, go vertically 22, hypotonuse is slope. angle is INV tan ( 22 / 100 ) = 12.407 degrees from horizontal
tan(11o) = 0.19438 =======
tan(22.5)=0.414213562
The answer is 0.2867.
it is tan 89.343 degrees
x = tan-1(5) = 78.69 degrees
ArcTan is another name for ;Inverse Tan' or 'Tan^*-1) Hence ArcTan(0.55431) = 29.00004157 degrees. Effectively 29 degrees.
Tan(5.2 degrees) = 0.0910 Tan(5.2 radians) = -1.8856