3.13
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cot 115 deg = - tan25 deg
22 % grade: go horizontally 100, go vertically 22, hypotonuse is slope. angle is INV tan ( 22 / 100 ) = 12.407 degrees from horizontal
tan (30 degrees) would be equal to 0.577350269.
If B is 90 degrees, Tan A is BC / AB. But I don't know what you mean by Tan A by 2.
0.813