3.13
cot 115 deg = - tan25 deg
22 % grade: go horizontally 100, go vertically 22, hypotonuse is slope. angle is INV tan ( 22 / 100 ) = 12.407 degrees from horizontal
tan (30 degrees) would be equal to 0.577350269.
If B is 90 degrees, Tan A is BC / AB. But I don't know what you mean by Tan A by 2.
45 degrees?
The cotangent function is the reciprocal of the tangent function, so cot(115 degrees) is equivalent to 1/tan(115 degrees). Since tan(115 degrees) is equivalent to -tan(65 degrees) due to the periodicity of the tangent function, cot(115 degrees) simplifies to -tan(65 degrees), which corresponds to option A.
cot 115 deg = - tan25 deg
The angle 300 degrees is in the fourth quadrant of the unit circle, where the tangent function is negative. Therefore, the sign of tan 300 degrees is negative. Specifically, tan 300 degrees can be calculated as tan(360 degrees - 60 degrees), which equals -tan(60 degrees), giving a negative value. Thus, tan 300 degrees is negative.
22 % grade: go horizontally 100, go vertically 22, hypotonuse is slope. angle is INV tan ( 22 / 100 ) = 12.407 degrees from horizontal
Tan 42 degrees = 0.9004
Tan(74 degrees) = 3.487414444.....
tan(11o) = 0.19438 =======
tan(22.5)=0.414213562
The answer is 0.2867.
it is tan 89.343 degrees
x = tan-1(5) = 78.69 degrees
ArcTan is another name for ;Inverse Tan' or 'Tan^*-1) Hence ArcTan(0.55431) = 29.00004157 degrees. Effectively 29 degrees.