cot 115 deg = - tan25 deg
22 % grade: go horizontally 100, go vertically 22, hypotonuse is slope. angle is INV tan ( 22 / 100 ) = 12.407 degrees from horizontal
tan (30 degrees) would be equal to 0.577350269.
If B is 90 degrees, Tan A is BC / AB. But I don't know what you mean by Tan A by 2.
45 degrees?
B: -tan(25)
cot 115 deg = - tan25 deg
22 % grade: go horizontally 100, go vertically 22, hypotonuse is slope. angle is INV tan ( 22 / 100 ) = 12.407 degrees from horizontal
Tan 42 degrees = 0.9004
tan(11o) = 0.19438 =======
tan(22.5)=0.414213562
The answer is 0.2867.
it is tan 89.343 degrees
x = tan-1(5) = 78.69 degrees
Tan(5.2 degrees) = 0.0910 Tan(5.2 radians) = -1.8856
The population of TAN Books is 22.
tan(30)=.5773502692