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tan (30 degrees) would be equal to 0.577350269.

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15y ago

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What is the exact trigonometric function value of cot 15 degrees?

cot(15)=1/tan(15) Let us find tan(15) tan(15)=tan(45-30) tan(a-b) = (tan(a)-tan(b))/(1+tan(a)tan(b)) tan(45-30)= (tan(45)-tan(30))/(1+tan(45)tan(30)) substitute tan(45)=1 and tan(30)=1/√3 into the equation. tan(45-30) = (1- 1/√3) / (1+1/√3) =(√3-1)/(√3+1) The exact value of cot(15) is the reciprocal of the above which is: (√3+1) /(√3-1)


What is the value of 30?

tan (30 degrees) would be equal to 0.577350269.


Find the value of a if tan 3a is equal to sin cos 45 plus sin 30?

If tan 3a is equal to sin cos 45 plus sin 30, then the value of a = 0.4.


How do you find the exact value of tan 150 degrees?

To find the exact value of (\tan 150^\circ), you can use the fact that (150^\circ) is in the second quadrant, where the tangent function is negative. The reference angle for (150^\circ) is (180^\circ - 150^\circ = 30^\circ). Therefore, (\tan 150^\circ = -\tan 30^\circ). Since (\tan 30^\circ = \frac{1}{\sqrt{3}}), it follows that (\tan 150^\circ = -\frac{1}{\sqrt{3}}), or (-\frac{\sqrt{3}}{3}) when rationalized.


What is the value of tan 15 degree in fraction?

The value of ( \tan 15^\circ ) can be calculated using the tangent subtraction formula: [ \tan(15^\circ) = \tan(45^\circ - 30^\circ) = \frac{\tan 45^\circ - \tan 30^\circ}{1 + \tan 45^\circ \tan 30^\circ} ] Substituting the known values ( \tan 45^\circ = 1 ) and ( \tan 30^\circ = \frac{1}{\sqrt{3}} ), we find: [ \tan(15^\circ) = \frac{1 - \frac{1}{\sqrt{3}}}{1 + 1 \cdot \frac{1}{\sqrt{3}}} = \frac{\sqrt{3} - 1}{\sqrt{3} + 1} ] Thus, ( \tan 15^\circ = 2 - \sqrt{3} ) in its simplest fractional form.


What is tan 30 degrees?

tan(30)=.5773502692


A skateboard ramp is built with a base length of 30 feet and a height of 13 feet.Which expression gives the value of x?

tan 13/30


By using trigonometric identities find the value of sin A if tan A a half?

The value of tan A is not clear from the question.However, sin A = sqrt[tan^2 A /(tan^2 A + 1)]


What is value of tan15' tan195'?

To find the value of (\tan(15^\circ) \tan(195^\circ)), we can use the identity (\tan(195^\circ) = \tan(15^\circ + 180^\circ) = \tan(15^\circ)). Thus, (\tan(195^\circ) = \tan(15^\circ)). Consequently, (\tan(15^\circ) \tan(195^\circ) = \tan(15^\circ) \tan(15^\circ) = \tan^2(15^\circ)). The exact value of (\tan^2(15^\circ)) can be computed, but it is important to note that it will yield a positive value.


How do you find the value of tan 135?

tan(135) = -tan(180-135) = -tan(45) = -1


What is the answer Tan inverse 0.5773?

30°


What is the value of tan 22.5 degrees?

tan(22.5)=0.414213562