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What age do infants double their birth weight?
Ideally When the baby reaches 1 year of age and quadruples it by age 2.
Can a baby be 5 pounds being full term?
Yes, a baby can be full term and weigh 5 pounds. While the average birth weight for full-term babies is typically between 5.5 to 8.8 pounds, some full-term babies may be smaller due to factors such as genetics, maternal health, or nutritional status during pregnancy. A weight of 5 pounds is classified as low birth weight, but it can still occur in otherwise healthy full-term infants. It's important for healthcare providers to monitor such infants for any potential health concerns.
What were the five leading causes of infant mortality in the Philippines in 2005?
The 5 biggest killers of infants in the Philippines are:1. Bacteria2. Respiratory distress of the infant3. Pneumonia4. Disorders related to short gestation (premature birth)5. congential pneumonia
What is the nth term of 3 1 -1 -3 -5?
The nth term is: 5-2n
What is the lowest term of 5 25?
1/5
What is the nth term of -1-6-11-16-21?
The given sequence is an arithmetic sequence where each term decreases by 5. The first term (a) is -1 and the common difference (d) is -5. The nth term can be calculated using the formula ( a_n = a + (n-1)d ). Therefore, the nth term is ( a_n = -1 + (n-1)(-5) = -1 - 5(n-1) = -5n + 4 ).
What is the 7th term in the sequence 1 5 25 125?
Each term is 5 times the previous term, so termr = 5(r-1) (with term1 = 1). So the 7th term is 57-1 = 56 = 15625.
What are the first five terms of the sequence 4n -1?
5
What is the 21st term in this sequence 1 -2 -5 -8 -11?
This is arithmetic progression with common difference of minus three...Formula:First Term +[ (number of term you want-1)*(common difference which is negative 3)]ExampleFor the 3RD term: -5=1+[(3-1)*(-3)]=1+[-6]= -5For 5TH term: -11=1+[(5-1)*(-3)]=1+(-12)=-11.: For the 21st term:=1+[(21-1)*(-3)]=1+[-60]= -59:D
What is 4 out of 5 plus 1 out of 2 in lowest term?
1 2/5
How do you write 20 percent as a fraction in lowest term?
1/5
If T(n)6n-1 what is the the 1st term?
The expression ( T(n) = 6n - 1 ) represents a sequence where ( n ) is the term number. To find the first term, substitute ( n = 1 ): ( T(1) = 6(1) - 1 = 6 - 1 = 5 ). Thus, the first term is 5.
