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This is arithmetic progression with common difference of minus three...
Formula:
First Term +[ (number of term you want-1)*(common difference which is negative 3)]
Example
For the 3RD term: -5
=1+[(3-1)*(-3)]
=1+[-6]
= -5
For 5TH term: -11
=1+[(5-1)*(-3)]
=1+(-12)
=-11
.: For the 21st term:
=1+[(21-1)*(-3)]
=1+[-60]
= -59
:D
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What is the 21st sequence in this sequence 1 -2 -5 -8 -11?
26073.
Nth term for 11 ,31,51,72?
The given sequence is 11, 31, 51, 72 The nth term of this sequence can be expressed as an = 11 + (n - 1) × 20 Therefore, the nth term is 11 + (n - 1) × 20, where n is the position of the term in the sequence.
What is the 32nd term of this sequence 94-1-6-11?
94-1-6-11
What is the nth term for the sequence 1 -2 -5 -8 -11?
The 'n'th term is [ 4 - 3n ].
What is the nth term in the sequence 3 7 11?
One of the infinitely many possible rules for the nth term of the sequence is t(n) = 4n - 1
What is the 21st sequence in this sequence 1 -2 -5 -8 -11?
26073.
If the 20th term in a sequence is 50 what is the 21st term?
Oh, dude, you just add one to the term number to get the next term. So, if the 20th term is 50, the 21st term would be the 20th term plus the common difference of the sequence. It's like basic math, man.
Nth term for 11 ,31,51,72?
The given sequence is 11, 31, 51, 72 The nth term of this sequence can be expressed as an = 11 + (n - 1) × 20 Therefore, the nth term is 11 + (n - 1) × 20, where n is the position of the term in the sequence.
A certain arithmetic sequence has the recursive formula an equals an-1 plus d If the common difference between the terms of the sequence is -11 what term follows the term that has the value 11?
an = an-1 + d term ar-1 = 11 difference d = -11 ar = ar-1 + d = 11 - 11 = 0 The term 0 follows the term 11.
What is the nth term of this sequence 3 5 7 9 11?
The nth term of the sequence is 2n + 1.
What is the 32nd term of this sequence 94-1-6-11?
94-1-6-11
Find the nth term 11,17,23,29?
I believe the answer is: 11 + 6(n-1) Since the sequence increases by 6 each term we can find the value of the nth term by multiplying n-1 times 6. Then we add 11 since it is the starting point of the sequence. The formula for an arithmetic sequence: a_{n}=a_{1}+(n-1)d
What is the nth term of the sequence 4 -1 -6 -11?
It works out as -5 for each consecutive term
1 -2 -5 -8 -11 what is the nth term in this sequence?
The 'n'th term is [ 4 - 3n ].
What is the nth term of the sequence 1 -2 -5 -8 -11?
The 'n'th term is [ 4 - 3n ].
What is the nth term for the sequence 1 -2 -5 -8 -11?
The 'n'th term is [ 4 - 3n ].
What is the nth term in the sequence 3 7 11?
One of the infinitely many possible rules for the nth term of the sequence is t(n) = 4n - 1
