This is arithmetic progression with common difference of minus three...
Formula:
First Term +[ (number of term you want-1)*(common difference which is negative 3)]
Example
For the 3RD term: -5
=1+[(3-1)*(-3)]
=1+[-6]
= -5
For 5TH term: -11
=1+[(5-1)*(-3)]
=1+(-12)
=-11
.: For the 21st term:
=1+[(21-1)*(-3)]
=1+[-60]
= -59
:D
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26073.
The given sequence is 11, 31, 51, 72 The nth term of this sequence can be expressed as an = 11 + (n - 1) × 20 Therefore, the nth term is 11 + (n - 1) × 20, where n is the position of the term in the sequence.
94-1-6-11
The 'n'th term is [ 4 - 3n ].
One of the infinitely many possible rules for the nth term of the sequence is t(n) = 4n - 1