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This is arithmetic progression with common difference of minus three...
Formula:
First Term +[ (number of term you want-1)*(common difference which is negative 3)]
Example
For the 3RD term: -5
=1+[(3-1)*(-3)]
=1+[-6]
= -5
For 5TH term: -11
=1+[(5-1)*(-3)]
=1+(-12)
=-11
.: For the 21st term:
=1+[(21-1)*(-3)]
=1+[-60]
= -59
:D
What else can I help you with?
What is the 21st sequence in this sequence 1 -2 -5 -8 -11?
26073.
Nth term for 11 ,31,51,72?
The given sequence is 11, 31, 51, 72 The nth term of this sequence can be expressed as an = 11 + (n - 1) × 20 Therefore, the nth term is 11 + (n - 1) × 20, where n is the position of the term in the sequence.
What is the 32nd term of this sequence 94-1-6-11?
94-1-6-11
What is the nth term for the sequence 1 -2 -5 -8 -11?
The 'n'th term is [ 4 - 3n ].
Find the rule for this sequence 1 6 11 16 21 26?
The sequence 1, 6, 11, 16, 21, 26 follows a linear pattern where each term increases by 5. The rule for the sequence can be expressed mathematically as ( a_n = 1 + 5(n - 1) ), where ( n ) is the term number. This means the first term (when ( n = 1 )) is 1, and each subsequent term adds 5 to the previous term.
What is the 21st sequence in this sequence 1 -2 -5 -8 -11?
26073.
Nth term for 11 ,31,51,72?
The given sequence is 11, 31, 51, 72 The nth term of this sequence can be expressed as an = 11 + (n - 1) × 20 Therefore, the nth term is 11 + (n - 1) × 20, where n is the position of the term in the sequence.
A certain arithmetic sequence has the recursive formula an equals an-1 plus d If the common difference between the terms of the sequence is -11 what term follows the term that has the value 11?
an = an-1 + d term ar-1 = 11 difference d = -11 ar = ar-1 + d = 11 - 11 = 0 The term 0 follows the term 11.
What is the nth term of this sequence 3 5 7 9 11?
The nth term of the sequence is 2n + 1.
What is the 32nd term of this sequence 94-1-6-11?
94-1-6-11
Find the nth term 11,17,23,29?
I believe the answer is: 11 + 6(n-1) Since the sequence increases by 6 each term we can find the value of the nth term by multiplying n-1 times 6. Then we add 11 since it is the starting point of the sequence. The formula for an arithmetic sequence: a_{n}=a_{1}+(n-1)d
What is the nth term for 11 21 31 41?
10n + 1
1 -2 -5 -8 -11 what is the nth term in this sequence?
The 'n'th term is [ 4 - 3n ].
What is the nth term of the sequence 1 -2 -5 -8 -11?
The 'n'th term is [ 4 - 3n ].
What is the nth term for the sequence 1 -2 -5 -8 -11?
The 'n'th term is [ 4 - 3n ].
What is the nth term of the sequence 4 -1 -6 -11?
It works out as -5 for each consecutive term
Find the rule for this sequence 1 6 11 16 21 26?
The sequence 1, 6, 11, 16, 21, 26 follows a linear pattern where each term increases by 5. The rule for the sequence can be expressed mathematically as ( a_n = 1 + 5(n - 1) ), where ( n ) is the term number. This means the first term (when ( n = 1 )) is 1, and each subsequent term adds 5 to the previous term.
