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What is 3 times 3 square root 2?
3(3 square root of 2) = 9(square root of 2)
What is the relation between square of 2 and square of 3?
The square of 3 is 2.25 times the square of 2
Is a square 2 or 3 dimensional?
A square is 2, but a cube is 3.
How did you find the square of each number?
The square of a number is that number times itself. Square of 2 is 2*2=4 Square of 3 is 3*3=9
What is the square root of 3 divided by 2 plus the square root of 3 divided by 2?
2 times the Square root of 3 + 4
Why is it called cubed and squared?
That is because a cube has 3 dimensions, and a square has 2.That is because a cube has 3 dimensions, and a square has 2.That is because a cube has 3 dimensions, and a square has 2.That is because a cube has 3 dimensions, and a square has 2.
What is Square root of 3 plus square root of 3?
sqrt(3) + sqrt(3) = 2*sqrt(3) NOT sqrt(3 + 2)
Square root 2 times square root 3 times square root 8?
square root 2 times square root 3 times square root 8
What is a fraction square?
It is the square of the numerator divided by the square of the denominator. Thus, for example, square(2/3) = square(2)/square(3) = 4/9
area of a box that is 3 ft wide 3 ft high and 3 ft long?
2*(3*3 + 3*3 + 3*3) = 2*27 = 54 square feet.2*(3*3 + 3*3 + 3*3) = 2*27 = 54 square feet.2*(3*3 + 3*3 + 3*3) = 2*27 = 54 square feet.2*(3*3 + 3*3 + 3*3) = 2*27 = 54 square feet.
Find the two numbers whose product is 1 and whose sum is 1?
x + y = 1xy = 1y = 1 - xx(1 - x) = 1x - x^2 = 1-x^2 + x - 1 = 0 or multiplying all terms by -1;(-x^2)(-1) + (x)(-1) - (1)(-1) = 0x^2 - x + 1 = 0The roots are complex numbers. Use the quadratic formula and find them:a = 1, b = -1, and c = 1x = [-b + square root of (b^2 - (4)(a)(c)]/2a orx = [-b - square root of (b^2 - (4)(a)(c)]/2aSox = [-(-1) + square root of ((-1)^2 - (4)(1)(1)]/2(1)x = [1 + square root of (1 - 4]/2x = [1 + square root of (- 3)]/2 orx = [1 + square root of (-1 )(3)]/2; substitute (-1) = i^2;x = [1 + square root of (i^2 )(3)]/2x = [1 + (square root of 3)i]/2x = 1/2 + [i(square root of 3]/2 andx = 1/2 - [i(square root of 3)]/2Since we have two values for x, we will find also two values for yy = 1 - xy = 1 - [1/2 + (i(square root of 3))/2]y = 1 - 1/2 - [i(square root of 3)]/2y = 1/2 - [i(square root of 3)]/2 andy = 1 - [1/2 - (i(square root of 3))/2)]y = 1 - 1/2 + [i(square root of 3))/2]y = 1/2 + [i(square root of 3)]/2Thus, these numbers are:1. x = 1/2 + [i(square root of 3)]/2 and y = 1/2 - [i(square root of 3)]/22. x = 1/2 - [i(square root of 3)]/2 and y = 1/2 + [i(square root of 3)]/2Let's check this:x + y = 11/2 + [i(square root of 3)]/2 +1/2 - [i(square root of 3)]/2 = 1/2 + 1/2 = 1xy = 1[1/2 + [i(square root of 3)]/2] [1/2 - [i(square root of 3)]/2]= (1/2)(1/2) -(1/2)[i(square root of 3)]/2] + [i(square root of 3)]/2](1/2) - [i(square root of 3)]/2] [i(square root of 3)]/2]= 1/4 - [i(square root of 3)]/4 + [i(square root of 3)]/4 - (3i^2)/4; substitute ( i^2)=-1:= 1/4 - [(3)(-1)]/4= 1/4 + 3/4= 4/4=1In the same way we check and two other values of x and y.
How do you add square roots to other square roots?
Other than by calculating the square roots and adding the results there is no general method. However, by factorising the number (of which the square root is being taken), the square root can be simplified which may let the square root be added. Examples: √2 + √8 = √2 + √(4×2) = √2 + √4 × √2 = √2 + 2√2 (1 + 2)√2 = 3√2 √12 + √27 = √(4×3) + √(9×3) = 2√3 + 3√3 = 5√3 (Remember that the radical sign (√) means the positive square root.)
