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Surface area = 96 cm2

So area of each face = 96/6 = 16 cm2

So length of each edge = sqrt(16) = 4 cm

So total length of all 12 edges = 12*4 = 48 cm.

By using Pythagoras's theorem in 3 dimensions, the length of the diagonal =

sqrt(42 + 42 + 42) = sqrt(16 + 16 + 16) = sqrt(48) = 6.93 cm (approx)

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Q: What is the Edge length of a cube and diameter if the surface area is 96cm2?
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