surface area of a cube
x = length of edge
surface area of 1 face is "x squared" written (x^2)
a cube has 6 surfaces, total surface area = 6(x^2)
96cm2 = 6(x^2)
solve for x
Surface area is 96cm2 Volume is 64cm3
Area = 6s2 where s is the length of an edge.
The surface area of a cube with an edge length of 5 inches is 150 square inches.
Edge length will be 8 cm
SA = 1,176 cm2
Surface area is 96cm2 Volume is 64cm3
Area = 6s2 where s is the length of an edge.
If you mean the length of one edge then it is 4cm because 4*4*6 = 96 square cm
Surface area = 96 cm2 So area of each face = 96/6 = 16 cm2 So length of each edge = sqrt(16) = 4 cm So total length of all 12 edges = 12*4 = 48 cm. By using Pythagoras's theorem in 3 dimensions, the length of the diagonal = sqrt(42 + 42 + 42) = sqrt(16 + 16 + 16) = sqrt(48) = 6.93 cm (approx)
The surface area of a cube with an edge length of 5 inches is 150 square inches.
Edge length will be 8 cm
The edge length is 5 inches.
The length of the edge is 7 cm
The surface area of a cube with an edge length of 5.5 yards is: 181.5 square yards.
determine the length of one edge of a cube that has a surface area of 864 square inches.
The edge length of this cube is: 8 cm
Surface area of two cubes = 6 times [ (length of first cube's edge)2 + (length of second cube's edge)2 ]