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What is the GCF of 5 ab and 6 b2?

Updated: 12/23/2022
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Q: What is the GCF of 5 ab and 6 b2?
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How do you rationalize the denominator in this expression 3 over quantity of 6 minus square root of 5?

Multiply the expression (fraction) by (6 + √5)/(6 + √5) (which is 1 and will not change its value).3/(6 - √5) x (6 + √5)/(6 + √5)= 3(6 + √5)/(6 - √5)(6 + √5)= 3(6 + √5)/(36-5) = 3(6 + √5)/31= 3/31(6 + √5)Remember:(a + b)(a - b) = a2 - ab + ab - b2= a2 - b2So if either a or b contains a square root, a2 and b2 will not, and so a2 - b2 will not!


Why does a plus b times a minus b work what is special about it and why does it work in questions like the root 6 plus root 5 times root 6 minus root 5 what is special about the answer?

(a + b)*(a - b) = a2 - ab + ab - b2 = a2 - b2 The expression is often referred to as DOTS = Difference Of Two Squares. What is special about it is that the answer contains only the squares of the two terms while the cross-products cancel out. So (√6 + √5)*(√6 - √5) = (√6)2 - (√5)2 = 6 - 5 = 1 The above result is used to simplify surds and, in particular, to rationalise their denominators.


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pls help me


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The GCF is 1.


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Can 30 plus ab plus 6b plus 5a be factored?

30 + ab + 6b + 5a = 5(a+6) + b(a+6) = (b+5)(a+6)