Multiply the expression (fraction) by (6 + √5)/(6 + √5) (which is 1 and will not change its value).
3/(6 - √5) x (6 + √5)/(6 + √5)
= 3(6 + √5)/(6 - √5)(6 + √5)
= 3(6 + √5)/(36-5) = 3(6 + √5)/31
= 3/31(6 + √5)
Remember:
(a + b)(a - b) = a2 - ab + ab - b2
= a2 - b2
So if either a or b contains a square root, a2 and b2 will not, and so a2 - b2 will not!
1.5
The idea is to get rid of the square root in the denominator. For this purpose, you must multiply numerator and denominator by the square root of 6 in this case.
6
Square root is a mathematical function whose argument needs to be a mathematical quantity or expression. Since helium is neither a mathematical quantity nor an expression, the question makes no sense.
An example may help. If you have the fraction 1 / (2 + root(3)), where root() is the square root function, you multiply top and bottom by (2 - root(3)). If you multiply everything out, you will have no square root in the denominator, instead, you will have a square root in the numerator. If the denominator is only a root, eg root(3), you multiply top and bottom by root(3).
1.5
Multiply everything by the square root of 3 minus the square root of 2 and then times that by 100 - 72 and divide that by 5
-26
The idea is to get rid of the square root in the denominator. For this purpose, you must multiply numerator and denominator by the square root of 6 in this case.
6
Yes. For example, the conjugate of (square root of 2 + square root of 3) is (square root of 2 - square root of 3).
Yes. The original denominator and its conjugate will form the factors of a Difference of Two Squares (DOTS) and that will rationalise the denominator but only if the radicals are SQUARE roots.
If you want to rationalize the denominator, then multiply numerator & denominator by sqrt(5), so 8*sqrt(5)/5 = approx 3.578
Yes, the expression 2 divided by 2 square root 3 can be simplified. To simplify this expression, we need to rationalize the denominator. Multiplying both the numerator and the denominator by the conjugate of the denominator (2 square root 3), we get (2 * 2 square root 3) / (2 * 2 square root 3 * 2 square root 3). This simplifies to 4 square root 3 / 12, which further simplifies to square root 3 / 3.
0.4
Square root is a mathematical function whose argument needs to be a mathematical quantity or expression. Since helium is neither a mathematical quantity nor an expression, the question makes no sense.
An example may help. If you have the fraction 1 / (2 + root(3)), where root() is the square root function, you multiply top and bottom by (2 - root(3)). If you multiply everything out, you will have no square root in the denominator, instead, you will have a square root in the numerator. If the denominator is only a root, eg root(3), you multiply top and bottom by root(3).