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How do you rationalize the denominator in this expression 3 over quantity of 6 minus square root of 5?
Multiply the expression (fraction) by (6 + √5)/(6 + √5) (which is 1 and will not change its value).3/(6 - √5) x (6 + √5)/(6 + √5)= 3(6 + √5)/(6 - √5)(6 + √5)= 3(6 + √5)/(36-5) = 3(6 + √5)/31= 3/31(6 + √5)Remember:(a + b)(a - b) = a2 - ab + ab - b2= a2 - b2So if either a or b contains a square root, a2 and b2 will not, and so a2 - b2 will not!
What is the GCF of 4 5 6?
The GCF is 1.
What is the gcf of 2 4 5 6?
The GCF is 1.
3x2squared plus bx-5 equals 0?
3x2 + bx - 5 = 0 ∴ 3x2 + bx = 5 ∴ x2 + bx/3 = 5/3 ∴ x2 + bx/3 + (b/6)2 = 5/3 + (b/6)2 ∴ (x + b/6)2 = (45 + b2) / 36 ∴ x + b/6 = ±[(45 + b2) / 36]1/2 ∴ x = [-b ± (45 + b2)1/2] / 6
What is the GCF of 2 5 and 6?
The greatest common factor of 2, 5, and 6 is 1.
How do you rationalize the denominator in this expression 3 over quantity of 6 minus square root of 5?
Multiply the expression (fraction) by (6 + √5)/(6 + √5) (which is 1 and will not change its value).3/(6 - √5) x (6 + √5)/(6 + √5)= 3(6 + √5)/(6 - √5)(6 + √5)= 3(6 + √5)/(36-5) = 3(6 + √5)/31= 3/31(6 + √5)Remember:(a + b)(a - b) = a2 - ab + ab - b2= a2 - b2So if either a or b contains a square root, a2 and b2 will not, and so a2 - b2 will not!
Why does a plus b times a minus b work what is special about it and why does it work in questions like the root 6 plus root 5 times root 6 minus root 5 what is special about the answer?
(a + b)*(a - b) = a2 - ab + ab - b2 = a2 - b2 The expression is often referred to as DOTS = Difference Of Two Squares. What is special about it is that the answer contains only the squares of the two terms while the cross-products cancel out. So (√6 + √5)*(√6 - √5) = (√6)2 - (√5)2 = 6 - 5 = 1 The above result is used to simplify surds and, in particular, to rationalise their denominators.
What is the GCF of 4 5 6?
The GCF is 1.
If 10 moles of A3 are reacted with excess B2 how many moles of AB will be produced 2A3 plus 3B2 6AB?
From the balanced equation, 2 moles of A3 react with 3 moles of B2 to produce 6 moles of AB. Therefore, if 10 moles of A3 are reacted, the ratio of moles of AB produced would be (10 moles A3 / 2 moles A3) * 6 moles AB = 30 moles AB.
2A3 plus 3B2 6AB If 10 moles of A3 are reacted with excess B2 how many moles of AB will be produced?
For every 2 moles of A3, 3 moles of B2 react to form 6 moles of AB. Since we have 10 moles of A3, we need to double the moles of B2 reacting, which would be 15 moles of B2 to fully react with the 10 moles of A3. This would produce 30 moles of AB.
Factor 6ab minus 6ac plus 6b squared minus 6bc?
6(ab - ac + b2 - bc)
What is the gcf of 2 4 5 6?
The GCF is 1.
Find the areas of the trapezoids.b1 = 4, b2 = 8, h = 2b1 = 5, b2 = 7, h = 4b1 = 5, b2 = 7, h = 4b1 = 12, b2 = 6, h = 3?
pls help me
What is the GCF of 2 5 6?
The GCF is 1.
What is the GCF of 5 and 6 and 25?
The GCF is 1.
What is the greatest common factor of 6 and 20 and 5?
The GCF of consecutive integers is 1.
What is the GCF of 6 5 4 and 16?
The GCF is 1.
