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solution with [OH-] = 2.5 x 10-9 , A solution with [H+] = 1.2 x 10-4, A solution with pH = 4.5
2
- log(2.3 X 10 -12 ) = 11.6 pH -----------------very little H + concentration in this solution.
-log(1.2 X 10^-5 M H(+)) = 4.9 pH H(+)
The solution to this equation is that h is equal to -4. You can substitute this value for h into the equation to get -4 x -9 - 6 plus 12 x -4 plus 40 equals 22, or 36 - 6 plus - 48 plus 40 equals 22.
1.79x10^-14 M
5.6
7.8
The pOH is 5,23.
7.5
pH and pOH are a measure of the concentration of the hydronium ions and hydroxyl ions respectively in the solution. pH = -log[H+] pOH = -log[OH-] and they are related: pH + pOH = 14
pH + pOH = 14 If the pH is 3.4, the pOH is 10.6
pH= -log[H+] pH + pOH = 14 pOH = 14 - pH pOH= -log[OH], so the antilog of -pOH will give you the OH concentration.
pH = - log([H+]) , pOH = - log([OH-] , pH + pOH = 14 [X] = concentration of X
If an aqueous solution has a pOH value of 10.7 and is at standard temperature and pressure, the pH value is 14 - 10.7 = 3.3. From the definition of pH, this means that the logarithm (to base 10) of the molar concentration of H+, [H+] is -3.3. This can be written as +0.7 - 4. The antilog of 0.7 is 5, to the justified number of significant digits. Therefore, [H+] = 5 X 10-4.
pH and pOH are both logarithmic scales measuring the acidity (or basicness) of a solution. pH is based on the amount of H+ (hydrogen ions), and pOH is based on the amount of OH- (hydroxide ions) in the solution. You can calculate pH if you know the H+ activity: pH = - log10 (H+) pOH is calculated the same way, except with OH- instead of the H+ ions. pOH is also equal to 14 - pH. This is because the pH and pOH scales go from 0 to 14. A solution that is very acidic will have a low pH number and a high pOH number. Conversely, a very basic solution will have a low pOH and a high pH. Water is a neutral solution and has a pH and pOH of 7, which is in the middle.
pOH = -log(10)[OH^-] pOH = -log(10) [ 48. x 10^-2] pOH = - (-1.31875...) pOH = 1.31875... pH = 14 - pOH pH = 14 - 1.31875... pH = 12.68124... pH = 12.68