2
pH = -log [H+] = -log (10-8) = 8
solution with [OH-] = 2.5 x 10-9 , A solution with [H+] = 1.2 x 10-4, A solution with pH = 4.5
-log(9.40 X 10^-4) = 3 pH
1.39
- log(2.3 X 10 -12 ) = 11.6 pH -----------------very little H + concentration in this solution.
-log(1.2 X 10^-5 M H(+)) = 4.9 pH H(+)
solution with [OH-] = 2.5 x 10-9 , A solution with [H+] = 1.2 x 10-4, A solution with pH = 4.5
1.15
6.15
1.15 (Apex)
apexvs answer 3.3
-log(9.40 X 10^-4) = 3 pH
1.39
1.70
- log(2.3 X 10 -12 ) = 11.6 pH -----------------very little H + concentration in this solution.
-log(1.2 X 10^-5 M H(+)) = 4.9 pH H(+)
its 7!
-log(1.5*10-11) = 9.8pH