solution with [OH-] = 2.5 x 10-9 , A solution with [H+] = 1.2 x 10-4, A solution with pH = 4.5
-log(9.40 X 10^-4) = 3 pH
1.39
- log(2.3 X 10 -12 ) = 11.6 pH -----------------very little H + concentration in this solution.
-log(1.2 X 10^-5 M H(+)) = 4.9 pH H(+)
solution with [OH-] = 2.5 x 10-9 , A solution with [H+] = 1.2 x 10-4, A solution with pH = 4.5
The pH of a solution with [H+] = 7.0 x 10^-2 is pH = -log(7.0 x 10^-2) = 1.15.
apexvs answer 3.3
-log(9.40 X 10^-4) = 3 pH
1.39
- log(2.3 X 10 -12 ) = 11.6 pH -----------------very little H + concentration in this solution.
The pH of a solution is calculated using the formula pH = -log[H+]. Plugging in the given value of [H+] = 7.0x10^-7, you would get a pH of 6.15 for this solution.
-log(1.2 X 10^-5 M H(+)) = 4.9 pH H(+)
-log(1.5*10-11) = 9.8pH
The pH of a solution with a H+ concentration of 7.0 x 10^-2 M can be calculated using the formula pH = -log[H+]. In this case, pH = -log(7.0 x 10^-2) = 1.15.
pH = -log(hydronium concentration) [Hydronium is H3O.-log(1 x 10-9) = 9
1.70