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The LCM of a^2b and b^2c is a^2b^2c
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How can you find the Lowest common denominator of four integers?
lcm(a,b,c,d) = lcm(lcm(a,b,c),d) = lcm(lcm(a,b),lcm(c,d))
What is the LCM of A B and C?
That depends on the values of A, B and C.
How do you calculate LCM of three numbers by pesudo code?
For this you will need a couple of helper algorithms. The first is the GCD (greatest common divisor) which is expressed as follows:procedure GCD (a, b) isinput: natural numbers a and bwhile ab doif a>blet a be a-belselet b be b-aend ifend whilereturn aThe second algorithm is the LCM (least common multiple) of two numbers:procedure LCM (a, b) isinput: natural numbers a and b return (a*b) / GCD (a, b)Now that you can calculate the GCD and LCM of any two natural numbers, you can calculate the LCM of any three natural numbers as follows:procedure LCM3 (a, b, c) isinput: natural numbers a, b and c return LCM (LCM (a, b), c)Note that the LCM of three numbers first calculates the LCM of two of those numbers (a and b) and then calculates the LCM of that result along with the third number (c). That is, if the three numbers were 8, 9 and 21, the LCM of 8 and 9 is 72 and the LCM of 72 and 21 is 504. Thus the LCM of 8, 9 and 21 is 504.
What is the LCM of 7 B C?
It depends on the values of B and C but without that knowledge, it is 7*B*C.
What is the least common multiple of decimals and fractions in C?
To calculate the least common multiple (lcm) of decimals (integers) and fractions you first need to calculate the greatest common divisor (gcd) of two integers: int gcd (int a, int b) { int c; while (a != 0) { c = a; a = b % a; b = c; } return b; } With this function in place, we can calculate the lcm of two integers: int lcm (int a, int b) { return a / gcd (a, b) * b; } And with this function in place we can calculate the lcm of two fractions (a/b and c/d): int lcm_fraction (int a, int b, int c, int d) { return lcm (a, c) / gcd (b, d); }
What LCM of 2 3 and 5 and why?
The LCM of 2, 3 and 5 is 30. The LCM of any three relatively prime numbers a, b and c is a*b*c, and here, 2 is a, 3 is b and 5 is c. Since 2, 3 and 5 are relatively prime, the LCM is 2*3*5=30.
How do you find the LCM and GCF of two no in c?
#include<stdio.h> main() { int a,b,i,lcm,gcf; printf("\n Enter two numbers"); scanf("%d%d",&a,&b); for(i=0;i<=a;i++) { if((b%i==0)&&(a%i==0)) { gcf=i; } } lcm=a*b/gcf; printf("\n GCF is %d and LCM is %d",gcf,lcm); }
If LCM and HCF is known of 2 number along with 1 number can you find second number?
Yes: product of a & b = LCM x HCF so b = (LCM x HCF)/a
What is the LCM of ab and bc?
It depends on whether or not a and c are coprime (have no factors in common). Suppose x is the greatest common factor of a and c, where x = 1 if a and c are coprime. ie GCF(a, c) = x then let a = x*m and c = x*n where m and n are coprime then LCM(ab, bc) = LCM(x*m*b, x*n*b) = x*m*n*b
What is the LCM of 4b2 and 6b3 A 2b2 B 12b2 C 12b3 D 24b3?
C. 12b3
How do you make a LCM program in c?
Based on gcd: int LCM (int a, int b) { . int d= gcd (a, b); . if (d==0) return 0; . else return a/d*b; }
the ratio of A to B is 2:3 and the ratio of B to C is 4:5. what is the ratio of A to C?
This deals with ratios and proportions. ⊱ ────── ✯ ────── ⊰ A : B = 2 : 3 B : C = 4 : 5. Now, to find A : B : C, we need to make the value of B equal in A : B ratio and B : C ratio. Here, Value of B in A : B ratio is 3; and B : C ratio is 4. LCM of 3 and 4 is 12. Therefore, we multiply 4 to the first ratio and 3 to the second ratio. A : B = 2 × 4 : 3 × 4 A : B = 8 : 12 Also, B : C = 4 × 3 : 5 × 3 B : C = 12 : 15 Now, we can combine A : B and B : C. A : B : C = 8 : 12 : 15.
