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What else can I help you with?
How can you find the Lowest common denominator of four integers?
lcm(a,b,c,d) = lcm(lcm(a,b,c),d) = lcm(lcm(a,b),lcm(c,d))
What is the LCM of A B and C?
That depends on the values of A, B and C.
What is the LCM of 7 B C?
It depends on the values of B and C but without that knowledge, it is 7*B*C.
How do you calculate LCM of three numbers by pesudo code?
For this you will need a couple of helper algorithms. The first is the GCD (greatest common divisor) which is expressed as follows:procedure GCD (a, b) isinput: natural numbers a and bwhile ab doif a>blet a be a-belselet b be b-aend ifend whilereturn aThe second algorithm is the LCM (least common multiple) of two numbers:procedure LCM (a, b) isinput: natural numbers a and b return (a*b) / GCD (a, b)Now that you can calculate the GCD and LCM of any two natural numbers, you can calculate the LCM of any three natural numbers as follows:procedure LCM3 (a, b, c) isinput: natural numbers a, b and c return LCM (LCM (a, b), c)Note that the LCM of three numbers first calculates the LCM of two of those numbers (a and b) and then calculates the LCM of that result along with the third number (c). That is, if the three numbers were 8, 9 and 21, the LCM of 8 and 9 is 72 and the LCM of 72 and 21 is 504. Thus the LCM of 8, 9 and 21 is 504.
What is the least common multiple of decimals and fractions in C?
To calculate the least common multiple (lcm) of decimals (integers) and fractions you first need to calculate the greatest common divisor (gcd) of two integers: int gcd (int a, int b) { int c; while (a != 0) { c = a; a = b % a; b = c; } return b; } With this function in place, we can calculate the lcm of two integers: int lcm (int a, int b) { return a / gcd (a, b) * b; } And with this function in place we can calculate the lcm of two fractions (a/b and c/d): int lcm_fraction (int a, int b, int c, int d) { return lcm (a, c) / gcd (b, d); }
What LCM of 2 3 and 5 and why?
The LCM of 2, 3 and 5 is 30. The LCM of any three relatively prime numbers a, b and c is a*b*c, and here, 2 is a, 3 is b and 5 is c. Since 2, 3 and 5 are relatively prime, the LCM is 2*3*5=30.
If LCM and HCF is known of 2 number along with 1 number can you find second number?
Yes: product of a & b = LCM x HCF so b = (LCM x HCF)/a
How do you find the LCM and GCF of two no in c?
#include<stdio.h> main() { int a,b,i,lcm,gcf; printf("\n Enter two numbers"); scanf("%d%d",&a,&b); for(i=0;i<=a;i++) { if((b%i==0)&&(a%i==0)) { gcf=i; } } lcm=a*b/gcf; printf("\n GCF is %d and LCM is %d",gcf,lcm); }
What is the LCM of 4b2 and 6b3 A 2b2 B 12b2 C 12b3 D 24b3?
C. 12b3
How do you make a LCM program in c?
Based on gcd: int LCM (int a, int b) { . int d= gcd (a, b); . if (d==0) return 0; . else return a/d*b; }
What is the LCM of ab and bc?
The least common multiple (LCM) of two numbers is the smallest number that is a multiple of both numbers. In this case, the LCM of ab and bc would be the product of the two numbers divided by their greatest common divisor (GCD), which is b. Therefore, the LCM of ab and bc is abc.
Is lcm of a and b equals lcm of a and b-a If so why?
The LCM of and b does not equal the LCM of a and b - a.
