It depends on the values of B and C but without that knowledge, it is 7*B*C.
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The LCM of 2, 3 and 5 is 30. The LCM of any three relatively prime numbers a, b and c is a*b*c, and here, 2 is a, 3 is b and 5 is c. Since 2, 3 and 5 are relatively prime, the LCM is 2*3*5=30.
The LCM of 7 and 49 is 49.
question: find the percentage A is of B or, 7 (A) is what percente of 35 (B) (B-A)/B x 100 =C. then subtract C from 100 B-A 35-7=28 /B 28/35=0.8 x 100 =C 0.8 x 100=80 - C 100-80=20. so, 7 is 20 percent of 35
To find the least common multiple (LCM) of 2b^2 and 6c^3, we first need to factorize both terms. The prime factorization of 2b^2 is 2 * b * b, and the prime factorization of 6c^3 is 2 * 3 * c * c * c. To find the LCM, we take the highest power of each prime factor that appears in either term, which gives us 2 * 3 * b^2 * c^3 = 6b^2c^3. Therefore, the LCM of 2b^2 and 6c^3 is 6b^2c^3.
88 b/c 4x22=88 8x11=88 and88x1=88