The Nth term of tn = 2n + 3 is 2N + 3.
Replace (substitute) the n by the term number to get its value.
t1 = 2 x 1 + 3 = 5
t2 = 2 x 2 + 3 = 7
t3 = 2 x 3 + 3 = 9
etc.
The nth term is: 5-2n
Nth term With the nth term you substitute the n for the term number (e.g. 50) so the 50th term in 2n+3 would be 2x50+3=103
The expression "2n 1" appears to be missing some operators or context. If you're referring to the nth term of a sequence where each term is defined as (2n + 1), then the nth term would be (2n + 1). This represents an arithmetic sequence where each term increases by 2, starting from 3 when (n = 1). If you meant something else, please clarify for a more accurate answer.
The sequence 1, 3, 5, 7, 9 is an arithmetic sequence where each term increases by 2. The nth term can be expressed as ( a_n = 2n - 1 ). Therefore, for any positive integer ( n ), the nth term of the sequence is ( 2n - 1 ).
2n+3. If 5 is the first term, then it is 2n + 3 (2×1 = 2 + 3 = 5 and 2×2 + 3 = 7)
3=2n
The nth term is: 5-2n
The nth term of the sequence is 2n + 1.
The nth term is 2n+5 and so the next number is 17
Nth term With the nth term you substitute the n for the term number (e.g. 50) so the 50th term in 2n+3 would be 2x50+3=103
The nth term of the sequence 2n + 1 is calculated by substituting n with the term number. So, the tenth term would be 2(10) + 1 = 20 + 1 = 21. Therefore, the tenth term of the sequence 2n + 1 is 21.
t(n) = 3*2n-1 Or just 3*2n
The expression "2n 1" appears to be missing some operators or context. If you're referring to the nth term of a sequence where each term is defined as (2n + 1), then the nth term would be (2n + 1). This represents an arithmetic sequence where each term increases by 2, starting from 3 when (n = 1). If you meant something else, please clarify for a more accurate answer.
The sequence 1, 3, 5, 7, 9 is an arithmetic sequence where each term increases by 2. The nth term can be expressed as ( a_n = 2n - 1 ). Therefore, for any positive integer ( n ), the nth term of the sequence is ( 2n - 1 ).
2n+3. If 5 is the first term, then it is 2n + 3 (2×1 = 2 + 3 = 5 and 2×2 + 3 = 7)
This is an arithmetic sequence with initial term a = 3 and common difference d = 2. Using the nth term formula for arithmetic sequences an = a + (n - 1)d we get an = 3 + (n - 1)(2) = 2n - 2 + 3 = 2n + 1.
2n + 1