The sequence 1, 3, 5, 7, 9 is an arithmetic sequence where each term increases by 2. The nth term can be expressed as ( a_n = 2n - 1 ). Therefore, for any positive integer ( n ), the nth term of the sequence is ( 2n - 1 ).
One of the infinitely many possible rules for the nth term of the sequence is t(n) = 4n - 1
The sequence 7, 4, 1, -2, -5 is an arithmetic sequence with a common difference of -3. To find the nth term, you can use the formula for the nth term of an arithmetic sequence: ( a_n = a_1 + (n-1)d ), where ( a_1 = 7 ) and ( d = -3 ). Thus, the nth term is given by ( a_n = 7 + (n-1)(-3) = 10 - 3n ).
The given arithmetic sequence is -1, 2, 5. To find the nth term, we first determine the common difference, which is 3 (2 - (-1) = 3 and 5 - 2 = 3). The formula for the nth term of an arithmetic sequence is given by ( a_n = a_1 + (n - 1)d ), where ( a_1 ) is the first term and ( d ) is the common difference. Thus, the nth term is ( a_n = -1 + (n - 1) \cdot 3 = 3n - 4 ).
The sequence "01234" consists of digits in ascending order, starting from 0. The nth term can be expressed as ( n - 1 ) for ( n = 1, 2, 3, 4, 5 ), where ( n ) represents the position in the sequence. Therefore, the nth term for this sequence is ( a_n = n - 1 ).
The sequence 3, 7, 11 is an arithmetic sequence where the first term is 3 and the common difference is 4. The nth term formula for an arithmetic sequence can be expressed as ( a_n = a_1 + (n - 1)d ), where ( a_1 ) is the first term and ( d ) is the common difference. Substituting the values, the nth term formula for this sequence is ( a_n = 3 + (n - 1) \cdot 4 ), which simplifies to ( a_n = 4n - 1 ).
The nth term of the sequence is 2n + 1.
The given sequence is an arithmetic sequence with a common difference of 4 between each term. To find the nth term of an arithmetic sequence, we use the formula: nth term = a + (n-1)d, where a is the first term, d is the common difference, and n is the term number. In this case, the first term (a) is -3, the common difference (d) is 4, and the term number (n) is the position in the sequence. So, the nth term of the given sequence is -3 + (n-1)4 = 4n - 7.
12 - 5(n-1)
One of the infinitely many possible rules for the nth term of the sequence is t(n) = 4n - 1
The sequence 7, 4, 1, -2, -5 is an arithmetic sequence with a common difference of -3. To find the nth term, you can use the formula for the nth term of an arithmetic sequence: ( a_n = a_1 + (n-1)d ), where ( a_1 = 7 ) and ( d = -3 ). Thus, the nth term is given by ( a_n = 7 + (n-1)(-3) = 10 - 3n ).
The given arithmetic sequence is -1, 2, 5. To find the nth term, we first determine the common difference, which is 3 (2 - (-1) = 3 and 5 - 2 = 3). The formula for the nth term of an arithmetic sequence is given by ( a_n = a_1 + (n - 1)d ), where ( a_1 ) is the first term and ( d ) is the common difference. Thus, the nth term is ( a_n = -1 + (n - 1) \cdot 3 = 3n - 4 ).
The nth term is 4n-1 and so the next term will be 19
The sequence "01234" consists of digits in ascending order, starting from 0. The nth term can be expressed as ( n - 1 ) for ( n = 1, 2, 3, 4, 5 ), where ( n ) represents the position in the sequence. Therefore, the nth term for this sequence is ( a_n = n - 1 ).
Well, darling, it looks like we have a simple arithmetic sequence here. The common difference between each term is 1, so the nth term formula is just n + 3. So, if you want the nth term for 4 5 6 7 8, it's n + 3. Hope that clears things up for ya!
The sequence 3, 7, 11 is an arithmetic sequence where the first term is 3 and the common difference is 4. The nth term formula for an arithmetic sequence can be expressed as ( a_n = a_1 + (n - 1)d ), where ( a_1 ) is the first term and ( d ) is the common difference. Substituting the values, the nth term formula for this sequence is ( a_n = 3 + (n - 1) \cdot 4 ), which simplifies to ( a_n = 4n - 1 ).
The given sequence is an arithmetic sequence with a common difference that increases by 1 with each term. To find the nth term of an arithmetic sequence, you can use the formula: nth term = a + (n-1)d, where a is the first term, n is the term number, and d is the common difference. In this case, the first term (a) is 3 and the common difference (d) is increasing by 1, so the nth term would be 3 + (n-1)(n-1) = n^2 + 2.
The sequence 1, 4, 7, 10, 13 is an arithmetic sequence where each term increases by 3. The first term (a) is 1, and the common difference (d) is 3. The nth term can be expressed using the formula: ( a_n = a + (n-1)d ). Thus, the nth term is ( a_n = 1 + (n-1) \times 3 = 3n - 2 ).