3
Magnitude of acceleration = (change in speed) / (time for the change) = 2/5 Acceleration = 0.4 meters per second2 north
Force is mass times acceleration. Assuming you mean an acceleration of 2 meters per second per second the force is 1 x 2 = 2N, south direction
Acceleration = change in velocity/change in time Acceleration = 96 miles per second - 32 miles per second/8 seconds = 8 miles per second per second or, better expressed 8 mi/s^2 ---------------
(change in velocity)/(change in time)=avg. acceleration (-30 m/s)/(15s)= -2 m/s2
Acceleration = 7.09 ms-2 G's = 7.09/9.8 = 0.72
5 metres per second squared
Magnitude of acceleration = (change in speed) / (time for the change) = 2/5 Acceleration = 0.4 meters per second2 north
Force is mass times acceleration. Assuming you mean an acceleration of 2 meters per second per second the force is 1 x 2 = 2N, south direction
Acceleration = change in velocity/change in time Acceleration = 96 miles per second - 32 miles per second/8 seconds = 8 miles per second per second or, better expressed 8 mi/s^2 ---------------
negative one mile per second per second
Use the 2 second rule. Leave 2 seconds between your car and the car in front of you.
8.44 ft/s^2
Force = mass times acceleration F = 1 x 2 = 2 Newtons
Use Newton's Second Law: force = mass x acceleration. Since both mass and acceleration are already in SI units, the answer will come out in Newton.Use Newton's Second Law: force = mass x acceleration. Since both mass and acceleration are already in SI units, the answer will come out in Newton.Use Newton's Second Law: force = mass x acceleration. Since both mass and acceleration are already in SI units, the answer will come out in Newton.Use Newton's Second Law: force = mass x acceleration. Since both mass and acceleration are already in SI units, the answer will come out in Newton.
"3 second" isn't a rate (an acceleration), it's a time.The force can be calculated by Newton's Second Law: just multiply the mass by the desired acceleration.
Acceleration is the change in velocity divided by change in time. The SI units for velocity and time are meters per second (m/s) and the second (s), respectively. Therefore, the SI unit of acceleration is meters per second per second (m/s^2). In this problem we have a car accelerating from 0 m/s to 61 m/s in 12 s. The acceleration is thus 61 m/s divided by 12 s to yield an answer of 5.1 m/s^2.
(change in velocity)/(change in time)=avg. acceleration (-30 m/s)/(15s)= -2 m/s2