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2A3 plus 3B2 6AB If 10 moles of A3 are reacted with excess B2 how many moles of AB will be produced?
For every 2 moles of A3, 3 moles of B2 react to form 6 moles of AB. Since we have 10 moles of A3, we need to double the moles of B2 reacting, which would be 15 moles of B2 to fully react with the 10 moles of A3. This would produce 30 moles of AB.
If 10 moles of A3 are reacted with excess B2 how many moles of AB will be produced 2A3 plus 3B2 6AB?
From the balanced equation, 2 moles of A3 react with 3 moles of B2 to produce 6 moles of AB. Therefore, if 10 moles of A3 are reacted, the ratio of moles of AB produced would be (10 moles A3 / 2 moles A3) * 6 moles AB = 30 moles AB.
Sum and difference of two cubes?
a3 + b3 = (a + b)(a2 - ab + b2) a3 - b3 = (a - b)(a2 + ab + b2
What is the sum and difference of two cubes?
a3 + b3 = (a + b)(a2 - ab + b2) a3 - b3 = (a - b)(a2 + ab + b2)
How do you factor the sum and difference of two cubes?
a3 + b3 = (a + b)(a2 - ab + b2) a3 - b3 = (a - b)(a2 + ab + b2)
How do you do two terms raised to third cube?
a3 - b3 = (a - b)(a2 + ab + b2) a3 + b3 = (a + b)(a2 - ab + b2)
How do you factorise a3-b3?
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Factorization of b4 -16b2c2 - 80 c4?
(b2 - 20c2)(b2 + 4c2)
How do you factor sum or difference of two cubes?
Sum and difference of two cubes is factored this way : a3 + b3 = (a + b)(a2 - ab + b2) a3 - b3 = (a - b)(a2 + ab + b2)
What is the formula of a3 plus b3?
(a+b)3=a3+b3+3ab(a+b) a3+b3=(a+b)3-3ab(a+b) a3+b3=(a+b)(a2-ab+b2)
How do you cube a binomial?
let binomial be (a + b)now (a+b)3 will be (a+b)(a+b)2 = (a+b)(a2 + 2ab+ b2) = a(a2+ 2ab+ b2) + b(a2 + 2ab+ b2) = a3+ 2a2b+ ab2 + a2b + 2ab2 + b3 = a3+ 2a2b+ ab2 + a2b + 2ab2 + b3 = a3 +3a2b + 3ab2 +b3 hope it helped... :D
Sum of two cubes?
a3+ b3 = (a + b)(a2 - ab + b2)
