LCM(a2b5, a3b3) The LCM of both numbers HAS to have the largest coefficient of both variables. For a, it's a3, and for b it is b5. So the LCM is a3b5.
a²-a = a(a-1)
you do (245x)
It is the opposite of Expanding The Brackets
2(3n+4)
a3*b3 = a3b3
LCM(a2b5, a3b3) The LCM of both numbers HAS to have the largest coefficient of both variables. For a, it's a3, and for b it is b5. So the LCM is a3b5.
Factorise fully is when brackets are involved in the equation
a²-a = a(a-1)
To factorise is to find the numbers that divide into the original number by only using prime numbers. For example factorise 20 = 2 times 2 times 5
to put into brackets
you do (245x)
The answer will depend on where the brackets are. In general the solution would be to expand all the brackets, combine like terms and then factorise.
6(t2s)
m(g-a)
-5
It is the opposite of Expanding The Brackets