0
LCM(a2b5, a3b3) The LCM of both numbers HAS to have the largest coefficient of both variables. For a, it's a3, and for b it is b5. So the LCM is a3b5.
a²-a = a(a-1)
you do (245x)
It is the opposite of Expanding The Brackets
2(3n+4)
LCM(a2b5, a3b3) The LCM of both numbers HAS to have the largest coefficient of both variables. For a, it's a3, and for b it is b5. So the LCM is a3b5.
a3*b3 = a3b3
To factorise is to find the numbers that divide into the original number by only using prime numbers. For example factorise 20 = 2 times 2 times 5
a²-a = a(a-1)
you do (245x)
to put into brackets
The answer will depend on where the brackets are. In general the solution would be to expand all the brackets, combine like terms and then factorise.
In the same way that you would factorise any other expressions that do not contain an equality sign depending on the expressions of which none have been given.
6(t2s)
It is the opposite of Expanding The Brackets
-5
m(g-a)