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What is the angle and the resultant vector of 10 km E and 5 km N and 7 km W?
Wiki User
∙ 11y ago
Relative to the starting point, the coordinates of the end point are (10-7, 5) or (3, 5)
So the magnitude of the resultant vector is sqrt(32 + 52) = sqrt(9 + 25) = sqrt(34) = approx 5.83 km.
The bearing (measured from North) is arctan(3/5) = arctan(0.6) = 031 degrees.
Wiki User
∙ 11y ago
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What is resultant velocity of the plane if a plane travels 100 km per hour to the north with a headwind of 25 km per hour towards the south?
The resultant velocity of a plane is 75 km/hr.
What is the resultant velocity of an airplane the normally flies 200 km per hour if it encounters a 50 km per hour tailwind?
If the airspeed is maintained at 200 km/hour with a 50 km/hour tailwind, then the speed over ground will be 250 km/hour (resultant velocity).
What is the vector sum of 5 km east and 5 km west?
zero, in any direction
What is my result if i calculate the magnitude of the resultant of a pair of 84 km h velocity vectors that are at right angles to each other?
If two vectors with equal magnitudes 'M' have perpendicular directions, then the resultant ismidway between them ... 45 degrees from each ... and the magnitude of the resultant isM sqrt(2).84 km/hr North + 84 km/hr East = 84 sqrt(2) = 118.794 km/hr Northeast (rounded).
What would be the vertical height on a 4 kilometer long inclination with an angle of 10 degrees?
4*sin(10) = 0.6945927107 or about 0.7 km
A sailboat sails 230 km E and then 340 km NE . Determine its resultant vector?
A = 230kmB = 340kmR = ?First, find the horizontal and vertical components of A& B.Ay = 0kmAx= 230kmNote: The angle, theta, is 45°, since NE is 45° from horizontal.By = 340km * sin(45°) = 240.42kmBx = 340km * cos(45°) = 240.42kmNow, add the respective components to get the Rcomponents.Ry = Ay + By = 0km + 240.42km = 240.42kmRx = Ax + Bx = 230km + 240.42km = 470.42kmFinally, use the Pythagorean theorem to get R.R = sqrt(Rx2 + Ry2) = 528.29kmTherefore, the resultant vector, R, is 528.29km.
A hiker walks 15MI due east then heads due north for 8 KM?
a hiker walks 15 mi due east, then heads due north for 8 km. what is the direction of the resultant vector?
Calculate the resultant of the pair of velocities 100 km north and 75 km south?
100 km and 75 km are displacements, NOT velocities. The resultant displacement is 25 km north,
What is resultant velocity of the plane if a plane travels 100 km per hour to the north with a headwind of 25 km per hour towards the south?
The resultant velocity of a plane is 75 km/hr.
What is resultant velocity of the plane if a plane travels 100 km per hour to the north with a tailwind wind of 25 km per hour towards the north?
The resultant velocity of a plane is 125 km/hr.
Is km s a vector quantity?
km/s can be either a vector or a scalar quantity. It is a unit of speed, which is scalar, but if this speed is in a specific direction, thereby becoming velocity, it is vector.
What is the resultant velocity of an airplane the normally flies 200 km per hour if it encounters a 50 km per hour tailwind?
If the airspeed is maintained at 200 km/hour with a 50 km/hour tailwind, then the speed over ground will be 250 km/hour (resultant velocity).
What is the resultant velocity of a boat if it travels south across a river at 14 km per hr. It encounters a current flowing from east to west at 9 km per hour?
The resultant velocity of a boat is 17 km/hr and the direction of the boat is SW.
What is the correct displacement for the following vectors 4 km south 2 km north 5 km south and 5 km north?
The resultant is 2 km South.
What is the vector sum of 5 km east and 5 km west?
zero, in any direction
What is my result if i calculate the magnitude of the resultant of a pair of 84 km h velocity vectors that are at right angles to each other?
If two vectors with equal magnitudes 'M' have perpendicular directions, then the resultant ismidway between them ... 45 degrees from each ... and the magnitude of the resultant isM sqrt(2).84 km/hr North + 84 km/hr East = 84 sqrt(2) = 118.794 km/hr Northeast (rounded).
What would be the vertical height on a 4 kilometer long inclination with an angle of 10 degrees?
4*sin(10) = 0.6945927107 or about 0.7 km
