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If a person walks 3 blocks East and 4 blocks North what is the displacement of the person?
5 blocks
Charlie travels Four blocks north Two east Three south and finally Two west How far is Charlie from his starting point?
The answer is one block. if you draw on a map where Charlie is, and move him in the correct directions, you will see that he is almost back where he began, only one block to the north of where he first started. This is a simple exercise in X and Y map coordinates. Setting the initial point at 0,0 and adding numerically, you can determine the final point. Let X be the points east and west (right and left as on a map). Let Y be the points north and south (up and down as on a map). Adding each change to the 0,0 starting point we get : * 4 blocks north = 0,4 * 2 blocks east = 2, 4 * 3 blocks south = 2, 1 * 2 blocks west = 0,1 Using this form, it is easy to see that he reversed his east-west movement completely, and only had a net change of +1 (north) on his north-south movement.
How do you get to Euclid Ohio from North Carolina?
North and a little west. Euclid is a suburb of Cleveland. I-77 will take you most of the way.
How are the pyramids positioned?
North, south, east, west,
What c always points north?
Compass
What is the correct displacement for the following vectors 4 km south km north 5 km south and 5 km north?
The displacement is a shortest distance. Here, the displacement will be 1 km. It will be in the North direction.
What is the correct displacement for the following vectors 4 km south 2 km north 5 km south 5 km north?
The displacement is a shortest distance. Here, the displacement will be 1 km. It will be in the North direction.
What is the correct displacement for the following vectors 4 km south 2 km north 5 km south .5 km north?
The displacement is a shortest distance. Here, the displacement will be 1 km. It will be in the North direction.
What is the correct displacement for the following vectors 4km south 2km north 5km south and 5km north?
The total displacement is 2km north, as the southward and northward displacements cancel each other out.
What is the correct displacement for the following vectors 4 km south 2 km north 2 km south and 5 km north?
The displacement is a shortest distance. Here, the displacement will be 1 km. It will be in the North direction.
What are displacement vectors of 2 km south and 6 km north and 5 km south and 6 km north combine to a total displacement of?
2 km south
What are not vectors?
north, 35 degrees north of east
If a Displacement vectors of 4 km south 2 km north 5 km north combine to a total displacement of?
To find the total displacement, we can break it down: the 4 km south and the 2 km north result in a net displacement of 2 km south (4 km south - 2 km north = 2 km south). Then, adding the 5 km north gives a total displacement of 3 km north (2 km south + 5 km north = 3 km north). Therefore, the total displacement is 3 km north.
What is the correct displacement for the following 4km south 2km north5km south5km north?
To find the correct displacement, we need to consider the net movement in the north-south direction. Starting from the origin, you move 4 km south, then 2 km north, resulting in a net movement of 2 km south. Next, moving 5 km south brings the total to 7 km south, and finally moving 5 km north results in a net position of 2 km south. Thus, the correct displacement is 2 km south.
What is the correct desplacment of the following vectors 4km south 2km north 5km south 5 km north?
4-2+5-5 = 2 km south. It's simple addition, keeping track of the plus and minus signs (south is plus, north is minus).
How do you find north south east west?
find the resultant of the following displacement a=20km 30south of east
What is the displacement of a hiker who travels 3.0 km east and then 4.0 km north?
The displacement of the hiker can be found by treating the eastward and northward movements as vectors. Using the Pythagorean theorem, the displacement is the square root of the sum of the squares of the distances traveled in each direction. In this case, the displacement is √(3.0 km)^2 + (4.0 km)^2 = √(9 km^2 + 16 km^2) = √25 km^2 = 5.0 km. Therefore, the displacement of the hiker is 5.0 km in a direction that is 53.1 degrees north of east.
