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Q: What is the angle formed at the intersection of th e diagonals of a rhombus?

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Rhombus: Adjacent sides are equal. Diagonals intersect at 90°. Measure of all interior angles not specific. Diagonals are not equal. Rectangle: Pair of opposite sides are equal. Measure of angle of intersection of diagonals not specific. Measure of all interior angles is 90°. Diagonals are equal.

Yes but there is no right angle forms.

Why a rhombus of course.

Yes

The diagonals are equal in length and cut each other at right angle.

Straight Angle :)

The quadrilateral that must have diagonals that are congruent and perpendicular is the square. This is because its diagonals form a right angle at its center.

Suppose that the parallelogram is a rhombus (a parallelogram with equal sides). If we draw the diagonals, isosceles triangles are formed (where the median is also an angle bisector and perpendicular to the base). Since the diagonals of a parallelogram bisect each other, and the diagonals don't bisect the vertex angles where they are drawn, then the parallelogram is not a rhombus.

The vertices of a rhombus have no right angles but its diagonals intersect each other at right angles.

The angle is 0.927 radians or, if you prefer, 53.13 degrees.

less than 90 degrees

A rhombus is a 4 equal sided quadrilateral that has no corner right angles at its vertices but its two diagonals meet each other at right angles.

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