Wi-Fi:
3G:
.data mult1 dw 2521H dw 3206H mult2 dw 0A26H dw 6400H ans dw 0,0,0,0 .code mov ax,@data mov ds,ax ; LEA SI,ans mov ax,mult1 mul mult2 mov ans,ax mov ans+2,dx mov ax,mult1+2 mul mult2 add ans+2,ax adc ans+4,dx adc ans+6,0 mov ax,mult1 mul mult2+2 add ans+2,ax adc ans+4,dx adc ans+6,0 mov ax,mult1+2 mul mult2+2 add ans+4,ax adc ans+6,dx mov ax,4C00h int 21h end
No.
ans 1. sending flowers ans 2. pruilen
Function mult 1.ans <- 0 2. For i=1 thru a by 1 a. Ans <- ans+b 3. Return (ans0 end mult function raise 1.ans <-1 2.for i=1 thru b by 1 3.return (ans) 4.end raise
Ans - 2+121=123
It is not possible to answer this question without knowing the actual expression used in the assignment statement. The following are merely example expressions showing some of the values that could be assigned to ans: int ans, p=100, q=50; ans = p + q; // ans = 150 ans = p * q; // ans = 5000 ans = p - q; // ans = -50 ans = p / q; // ans = 2 ans = p % q; // ans = 0
yes[ans]
Is it a. 3n square and 3n ans. 3n b. 3n *2 and 3n ans.3n ans. 3n for both!!
They could be: 1 cubed+2 cubed = 9 and 3 squared = 9 very bad ans
Elle a deux ans.
the ans is 0.25
2:15