61 x 02 = 122
6-1x0+2/2=7 Order of operations requires that multiplication and division be performed first. 6-(1x0)+(2/2)=7 I've added parenthesis to make the math a bit clearer. 6-(0)+(1)=7 And Voila, the answer is 7.
7
7
7
1
7. But, the answer can also be 4. This is an ambiguous question. If the question is interpreted in this way : 6- (1x0) + (2/2), then the answer is 1 [6-0+1 = 7]. But, if the question is interpreted as : [6-(1x0) + 2]/2 ------- when the whole term is divided by two, the answers is 2 [(6-0+2)/2 = 8/2 = 4].
2, realiza-se a multiplicação primeiro
Here: 9+8+7+6+4+3+2+1x0=0 and then 0+5=5
7 6 - 1 x 0 + 1 1. Multiplication first (PEMDAS), 1x0 = 0 2. Division, Addition, Subtraction.... 6-0+1= 7
If that's 6 x 102 divided by 2, the odpowiedz is 3 x 102 If that's 6 - 1 x 0 + 2/2, the order of operations states that multiplication and division take place before addition and subtraction. 1 x 0 = 0 and 2/2 = 1 6 - 0 + 1 = 7
b0m 1x0
1+1+1+1x0 1+1+1+0 1+1+1 3