Depending on whether or not there are implied brackets: x + 62 = x + 36 (x + 6)2 = x2 + 12x + 36
6x + 10 = 72 6x = 72 - 10 x = 62/6 x = 10.3333
10x + 2 - 62 Subtract '2' from both sides 10x = 60 Divide both sides by '10'/ x = 6 The answer!!!!!
If you mean: -5x+14x = 48+14 then 9x = 62 and the value of x equals 62/9 = 6.'8' recurring '8'
62 x 1/6 = 62 x 0.16667 = 10.33354
X=-33
It is: 62+8-7-6 = 57
The question is the equivalent to asking for the solution to the equation: 149 + x = 211 (solve for x) It is 149 plus 62 = 211, i.e. x = 62
56 + 6 = 62
13
The first ten positive integer multiples of 62 are: 1 x 62 = 62 2 x 62 = 124 3 x 62 = 186 4 x 62 = 248 5 x 62 = 310 6 x 62 = 372 7 x 62 = 434 8 x 62 = 496 9 x 62 = 558 10 x 62 = 620
62 = (6 x 10) + (2 x 1)