Wiki User
∙ 2012-11-19 23:34:14X=4.2666666666667
Wiki User
∙ 2012-11-19 23:34:14Double first equation: 10x + 2y = 10Subtract second equation: 7x = 7x = 1, y = 0
It is an equation and the value of x is 8
7x = -3y + 12
Why not? The statement is trivially true, meaning it holds for all values of x.
7x + 9 = 51 7x = 42 x = 42/7 = 6
-2x + 8 = 7x - 10 is technically an equation, in and of itself.
7x + y = 8 Subtract 7x from each side of the equation: y = -7x + 8
Double first equation: 10x + 2y = 10Subtract second equation: 7x = 7x = 1, y = 0
x2 - 7x = 60 x2 - 7x - 60 = 0 (x - 12) (x + 5) = 0 x = 12 or x = -5
It is an equation and the value of x is 8
7x = -3y + 12
Why not? The statement is trivially true, meaning it holds for all values of x.
7x + 9 = 51 7x = 42 x = 42/7 = 6
It is an equation and the value of x is 2
Im guessing that the equation is 7x - 2y +3z= 19 so the answer is 7x + 3z= 19
x = 4 You have to add the 8x and 7x to get 15x and then divide 60 by 15 to get x by itself.
It is an equation and the value of x is 12