To find the expression for ((5x - y)(3x^2 - 3xy + 2y^2)), you need to distribute (5x) and (-y) across each term in the second polynomial. This results in:
[ 5x(3x^2) - 5x(3xy) + 5x(2y^2) - y(3x^2) + y(3xy) - y(2y^2) ]
Simplifying this gives:
[ 15x^3 - 15x^2y + 10xy^2 - 3x^2y + 3xy^2 - 2y^3 ]
Combining like terms results in:
[ 15x^3 - 18x^2y + 13xy^2 - 2y^3 ]
All six of them
4x^2+2xy-3y^2-2x^2+5xy-2y2Collect the like terms=2x^2+7xy-5y^2We cannot factorise it because the end term is a negative whilst the second-last term is positive.
It is: 7a/5xy
To find the derivative of the expression (5xy) with respect to (x), we can use the product rule. The derivative is given by ( \frac{d}{dx}(5xy) = 5 \left( x \frac{dy}{dx} + y \right) ). Thus, the derivative of (5xy) is (5y + 5x \frac{dy}{dx}).
9
All six of them
4x^2+2xy-3y^2-2x^2+5xy-2y2Collect the like terms=2x^2+7xy-5y^2We cannot factorise it because the end term is a negative whilst the second-last term is positive.
You need at least two terms to find a GCF.
(-5xy):(-xy)=
It is: 7a/5xy
x2 + 5xy - 18y2 can not be factored.
5xy+4=9
What is : 5xy- x2t + 2xy + 3x2t
To find the derivative of the expression (5xy) with respect to (x), we can use the product rule. The derivative is given by ( \frac{d}{dx}(5xy) = 5 \left( x \frac{dy}{dx} + y \right) ). Thus, the derivative of (5xy) is (5y + 5x \frac{dy}{dx}).
9
2(y - 3)(y - 10)
It is: 5