You need at least two terms to find a GCF.
(5x + y)(25x^2 - 5xy + y^2)
3y = 5xy = x + 23y = 5x3(x + 2) = 5x3x + 6 = 5x3x - 3x + 6 = 5x - 3x6 = 2x6/2 = 2x/23 = xy = x + 2 = 3 + 2 = 5Thus, the solution of the set is (3, 5)Check:
colinear and non-colinear are terms that are used when describing points in space, not the graph of a function. Maybe what you meant is "Is the function linear?" The answer to that question is no.
x2 + 5xy - 18y2 can not be factored.
What is : 5xy- x2t + 2xy + 3x2t
Without an equality sign the given expression can't be considered to be a linear equation.
5xy+4=9 is the problem, right? 5xy+4=9. Now subtract the 4 from both sides. 5xy=5. Ok, then, that looks less scary. Now, divide both sides by 5, to get xy=1. Hmm, a lot simpler. Now, divide both sides by x to get y by itself. So, y=1/x. Alright. That's your line! No, its not a straight line. There is a vertical asymptote where x=0, and the two segments aren't straight. But that's a simpler form of the equation. Hope that helped!
It is 5xy + 5x.
The GCF is 5xy.
All six of them
In the given expression you replace x by 2 and y by 1. Thus 5xy + 7x2 - 12y = 5*x*y + 7*x2 - 12*y = 5*2*1 + 7*22 - 12*1 = 10 + 28 - 12 = 26