Q: Factoring x2 plus 5xy-18y2

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y=b+x+x^2 This is a quadratic equation. The graph is a parabola. The quadratic equation formula or factoring can be used to solve this.

When factoring it is fairly easy to check your answer. Say we want to factor x2+9x+14=0 (x+7)(x+2)=0 now if we want to check then we can just multiply these together and we should get the original polynomial... x2+2x+7x+14=0 x2+9x+14=0

x2+3x+2=0 (x+2)(x+1)=0 x=-2 or -1

There is no expansion for x2 + y2

X2 + 4xx(x + 4)=======

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(x + 8)(x + 2)

x2 - 14x + 49 = (x - 7)2

x2 + 5x - 6 = x2 + 6x - x - 6 = x(x + 6) - 1(x + 6) = (x - 1)(x + 6)

(x+8)^2=105

An equation would be....,X2 - 10X + 16 = 0easy factoring(X - 2)(X - 8)==========So.X = 2====

35 + 40x + 5x2 = 5(7 + 8x + x2) = 5(7 + x)(1 + x)

x2+6x+9 = x+3 x2+6x-x+9-3 = 0 x2+5x+6 = 0 Solve by factoring or with the help of the quadratic equation formula: (x+3)(x+2) = 0 Therefore: x = -3 or x = -2

x2-64 = (x-8)(x+8)

This can be factored as (x+3)(x+2). (To do this factoring, in this case you look for two numbers that, when multiplied, give 6, and when added, give 5.)

y=b+x+x^2 This is a quadratic equation. The graph is a parabola. The quadratic equation formula or factoring can be used to solve this.

The roots are -3 and -7. Easily by factoring and setting each factor equal to 0. The factors are x + 7 and x +3.

When the co-efficient of x2 is 1