a≠ 0,LCD = a3
3/a + 2/a2 - 1/a3
= (3/a)(a2/a2) + (2/a2)(a/a) - 1/a3
= 3a2/a3 + 2a/a3- 1/a3
= (3a2 + 2a -1)/a3
Would you mind typing it out for me? I don't quite understand exactly what you are asking. For example, x to the second power minus 4x over x to the second power minus 16 would be... x^2-4x/x^2-16 Do you mind typing it out like that? Because what you wrote makes no sense at all.
3^-1 = 1 over (3 to the power of 1) = 1/3, one third. a minus power is the same as a normal power but with a 1 above it.
1/2r
15
If you multiplied all the terms by y2, you could simplify this to -3y3.
1 divided by 25 multiplied by z to the third power
Type this: ((w^2)/(w-6))((w^2-4w-12)/(w^2-3w) Into wolframalpha.com. It will give you the answer (too much for this box).
Yes. 3n2/12n3 = 1/4n
-3/16 since the answer is negative (the second number is larger) and the problem is subtraction you minus the second number from the first then make the answer negative and you have the answer
7 and one third minus 3 and 9 tenths is six and 13 over 30 3 and 13/30
3 1/3 minus 8/3 is 2/3.
2x 2x to the second