8 + 2y = 6
Subtract 8 from both sides: 2y = -2
Divide both sides by 2: y = -1
x = 2y = 4
-2y=x+8 is the answer
Well lets see: 2y = 6x+8 y=3x+4 does not equal y=3x+6 So they are not the same.
-6
3y-8+5y = 2y-39 3y+5y-2y = -39+8 6y = -31 y = -31/6
5y+8 = 7y-6 5y-7y = -6-8 -2y = -14 y = 7
6+2y=8 -6 -6 2y=2 /2 /2 y=1
2X + 5Y = 6 5Y = - 2X + 6 Y = - 2/5X + 6/5 ----------------------------------and 5X - 2Y = 8 2Y = - 5X + 8 Y = - 5/2 + 4 ------------------- Look like intersecting lines, though not perpendicular
The values are: x = -6 and y = 10
3y - 3 = 2y + 5 3y - 2y = 5 + 3 y = 8
If the two equations are (i) 4x + 2y = 12 and (ii) x + 2y = 6, proceed as follows: Rewrite (ii) as x = 6 - 2y; substitute this expression for x into (i) to result in 4(6 - 2y) + 2y = 12, or 24 - 8 y + 2y = 12, or - 6 y = 12 -24 = -12, or y = -12/-6 = 2. Then, back to (ii) again, x = 6 - 2(2) = 2.
x = 1 and y = 6 so the lines intersect at the point (1, 6)