The values are: x = -6 and y = 10
If: 3x+2y = 5x+2y = 7 Then: 3x+2y = 7 and 5x+2y = 7 Subtract the 1st equation from the 2nd equation: 2x = 0 or x = o By substitution: x = 0 and y = 3.5
Both of them are equations!The solution is (x, y) = (2, 1).
2y = 6x+2
3x plus 2y - 3 is an expression. There can be no answer to one expression and one linear equation in two variables.
Double first equation: 10x + 2y = 10Subtract second equation: 7x = 7x = 1, y = 0
3x + 2y = 8 This is an equation. It could be the equation of a line.
If: 3x+2y = 5x+2y = 14 Then: 3x+2y = 14 and 5x+2y =14 Subtract the 1st equation from the 2nd equation: 2x = 0 Therefore by substitution the solutions are: x = 0 and y = 7
3x + 2y = 12 ie 2y = 12 - 3x so y = 6 - 3x/2
If: 3x+2y = 5x+2y = 7 Then: 3x+2y = 7 and 5x+2y = 7 Subtract the 1st equation from the 2nd equation: 2x = 0 or x = o By substitution: x = 0 and y = 3.5
Both of them are equations!The solution is (x, y) = (2, 1).
2y = 6x+2
3x plus 2y - 3 is an expression. There can be no answer to one expression and one linear equation in two variables.
2y-3x=4
The equation can be simplified to show a value of Y in terms of X. 3X + 2Y +2 = 4Y + 4 3X + 2 = 2Y + 4 3X -2 = 2Y and 2Y = 3X - 2 means that Y = (3/2 X) -1
3x + 2y = 8 2y=8-3x y=4-1.5x A quadratic has x^2 This is the equation of a line with negative slope.
Double first equation: 10x + 2y = 10Subtract second equation: 7x = 7x = 1, y = 0
If: -3x+2y = 12 Then: y = 1.5x+6 in slope-intercept form