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What is the answer for The surface area of a square pyramid is 85 square meters. The base length is 5 meters. What is the slant height?
Wiki User
∙ 6y ago
So the base is 25 meters squared, that leaves 60 for the triangles.
the equation for triangles is base x height x 1/2
5 times 6 is 30 divide by 2 is 15 times 4 is 60.
the answer is 6
Pickles MC
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If a particular right square based pyramid has a volume of 63690 cubic meters and a height of thirty meters What is the number of meters in the length of the lateral height segment AB of a pyramid?
The formula for the volume of a pyramid such as you described would be: V = 1/3Ah where A is the area of the base (a square in this case) and h is the height of the pyramid. You know the volume and the height, so you can plug them into that formula to solve for A, the area of the square base: 63690 = 1/3A(30). A = 6369 square meters. Knowing the area of the square, and the fact that the formula for the area of a square is A = s2 where s is the length of a side, you can find the length of s by taking the square root of 6369. s = about 79.8 meters. The next steps will require some thinking about what that pyramid looks like and what the length of a lateral height segment would represent. Drawing a diagram often helps. If I understand correctly what you mean by "lateral height segment" of the pyramid, meaning the length of the segment from the center of a side at the bottom to the vertex at the top, that length would represent the hypotenuse of a right triangle whose legs are 30 meters (the inside height of the pyramid) and about 39.9 meters (half the length of a side, in other words the distance from the point at the center of the base to the center of the side). You can use the Pythagorean theorem to find that length: c2 = a2 + b2 c2 = 302 + 39.92 c2 = 900 + 1592 c2 = 2492 c = 49.9 meters (approximately)
If a square pyramid has a base of 6.3 meters and a height of 4 meters what is the surface area?
To find the height of the triangles on the sides of the pyramid, we use pythagorean theorem. We slice vertically through the center of the pyramid to find a triangle with base of 6.3 and height of 4. Using the pythagorean theorem, we can find that each side of this triangle will be sqrt(42+3.152). This will be the height of the triangles on the sides of the pyramid, let's call it h.So, the area of each triangle will be 1/2*6.3*h. There are 4 of these triangles.The area of the base of the pyramid will be 6.32The total surface area of the pyramid will be SA = 2*6.3*sqrt(42+3.152)+6.32SA ~= 103.84 m2
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If a particular right square based pyramid has a volume of 63690 cubic meters and a height of thirty meters What is the number of meters in the length of the lateral height segment AB of a pyramid?
The formula for the volume of a pyramid such as you described would be: V = 1/3Ah where A is the area of the base (a square in this case) and h is the height of the pyramid. You know the volume and the height, so you can plug them into that formula to solve for A, the area of the square base: 63690 = 1/3A(30). A = 6369 square meters. Knowing the area of the square, and the fact that the formula for the area of a square is A = s2 where s is the length of a side, you can find the length of s by taking the square root of 6369. s = about 79.8 meters. The next steps will require some thinking about what that pyramid looks like and what the length of a lateral height segment would represent. Drawing a diagram often helps. If I understand correctly what you mean by "lateral height segment" of the pyramid, meaning the length of the segment from the center of a side at the bottom to the vertex at the top, that length would represent the hypotenuse of a right triangle whose legs are 30 meters (the inside height of the pyramid) and about 39.9 meters (half the length of a side, in other words the distance from the point at the center of the base to the center of the side). You can use the Pythagorean theorem to find that length: c2 = a2 + b2 c2 = 302 + 39.92 c2 = 900 + 1592 c2 = 2492 c = 49.9 meters (approximately)
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If a square pyramid has a base of 6.3 meters and a height of 4 meters what is the surface area?
To find the height of the triangles on the sides of the pyramid, we use pythagorean theorem. We slice vertically through the center of the pyramid to find a triangle with base of 6.3 and height of 4. Using the pythagorean theorem, we can find that each side of this triangle will be sqrt(42+3.152). This will be the height of the triangles on the sides of the pyramid, let's call it h.So, the area of each triangle will be 1/2*6.3*h. There are 4 of these triangles.The area of the base of the pyramid will be 6.32The total surface area of the pyramid will be SA = 2*6.3*sqrt(42+3.152)+6.32SA ~= 103.84 m2
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