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If a square pyramid has a base of 6.3 meters and a height of 4 meters what is the surface area?
Wiki User
∙ 14y ago
To find the height of the triangles on the sides of the pyramid, we use pythagorean theorem. We slice vertically through the center of the pyramid to find a triangle with base of 6.3 and height of 4. Using the pythagorean theorem, we can find that each side of this triangle will be sqrt(42+3.152). This will be the height of the triangles on the sides of the pyramid, let's call it h.
So, the area of each triangle will be 1/2*6.3*h. There are 4 of these triangles.
The area of the base of the pyramid will be 6.32
The total surface area of the pyramid will be SA = 2*6.3*sqrt(42+3.152)+6.32
SA ~= 103.84 m2
Wiki User
∙ 14y ago
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