5,600
There are 101 of them including 1 and 201. The other 99 begin with the numbers 3, 5, 7... and then keep adding 2 and you will get them all.
The sum of all the numbers from 101 through 200 is 15,050.
The total is 5050.There are 49 pairs of numbers that equal 100 (1+99, 2+98...) and the other unpaired numbers are 50 and 100.Similarly, you can add 1 to 100 you get 101, if you add 2 to 99 you get 101 if you do it all the way down to 50+51 there is 50 pairs of 101. Then you multiply 101 by 50 to get 5050.The process:You are adding 1 + 2 + 3 + 4 + 5...+ 96 + 97 + 98 + 99 + 100. If you were adding some portion that began with a number other than 1, or if you were adding just odds or evens, the method would be different.Notice that the first and last numbers add up to 101 (1 + 100). So do the second and second-to-last (2 + 99). In fact, all of the numbers pair up like this, always adding up to 101.If you paired up the numbers this way, you'd have 50 pairs, which is half of 100. Each pair's sum is 101.The formula that summarizes this trick uses "n" to stand for the top number, in this case 100. N multiplied by (n + 1), divided by 2, gives you the answer. (100 x 101) / 2 is the same as 50 x 101. 50 x 101 = 5050.
Adding up all the even numbers from the first (2) to the fiftieth (100): [(100 + 2) / 2] x 50 = 2550 Can you see the logic of this method?
101
-99
101
The answer is zero !
Instead of adding each digit in turn, acknowledge that there are 100 numbers to add, and then multiply that by the average of 1 and 100.Ie. 100×(1+100)÷2=100×101;÷2100×101;÷2=50×101=5050So, in short, the answer is: 5050
3,6,9,12,15,18,21,24,27,30,33,36,39,42,46,49,52,55,58,61,64,67,80,83,86,89,92, 95,98 and 101 They are all the numbers I know. XD
7500
101