3,6,9,12,15,18,21,24,27,30,33,36,39,42,46,49,52,55,58,61,64,67,80,83,86,89,92,
95,98 and 101
They are all the numbers I know. XD
4 is a multiple of three numbers.
If you take three consecutive odd (or three consecutive even) numbers, one of the three will always be a multiple of 3.If you take three consecutive odd (or three consecutive even) numbers, one of the three will always be a multiple of 3.If you take three consecutive odd (or three consecutive even) numbers, one of the three will always be a multiple of 3.If you take three consecutive odd (or three consecutive even) numbers, one of the three will always be a multiple of 3.
A multiple of 3 Also a multiple of 6.
128
These do exist.
Calculate the least common multiple of the three numbers. Any multiple of that has all those numbers as factors.
EVERY three consecutive numbers add to a multiple of 3: Proof: numbers are n, n + 1 and n + 2. The total is 3n + 3 or 3(n + 1) This means that for any three consecutive numbers, the total is 3 times the middle number.
The answer is 9 × 6 × 7
idont know
I'll guess those are three-digit numbers. The way to find if a number is a multiple of 3 is to total its digits. If that total is a multiple of 3, the whole number is a multiple of 3. 285 and 126, yes. 770, 176, 410, 452, 650, no.
That doesn't work. The number has to be divisible by three. Any three consecutive numbers add up to a multiple of three.
It means write down three pairs of numbers that are relatively prime like 4 and 9, 5 and 6, 13 and 25