answersLogoWhite

0

What is the answer of this 3 kg m?

Updated: 12/19/2022
User Avatar

Wiki User

12y ago

Best Answer

It would help if there were more of the question!

User Avatar

Wiki User

12y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: What is the answer of this 3 kg m?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

Does engine oil have good density?

Yes engine oil has density but the temperature varies. For 0 degrees Celsius it is 899.0 kg/m^3. For 20 degrees it is 888.1 kg/m^3. For 40 degrees it is 876.0 kg/m^3. For 60 degrees it is 863.9 kg/m^3. For 80 degrees it is 852.0 kg/m^3. For 100 degrees it is 840.0 kg/m^3. For 120 degrees it is 828.9 kg/m^3. For 140 degrees it is 816.8 kg/m^3. For 150 degrees it is 810.3 kg/m^3.


How do you tabulate the density of water from 15C to 30C to four or more significant figures by degree?

From the Steam Tables I get the following: T v sub f d ( kg / m^3 ] 15.0 C 0.001001 m^3/ kg 999.0 kg / m^3 20.0 C 0.001002 m^3/ kg 998.0 kg/ m^3 25.0 C 0.001003 m^3 / kg 1001 kg / L^3 30.0 C 0 .001004 m^3 / kg 996.0 kg/m^3 -------------------- Search also NISTIR 6969, table 9.8 (it's free on Internet) or a density calculator.


How do you measure the volume of a rock using its bulk density?

mass [kg] = volume [m^3] * density [kg / m^3] From Newton's 2nd law of motion, weight [N] = mass [kg] * 9.8 [m/s^2] = volume [m^3] * density [kg / m^3] * 9.8 [m/s^2]. Rearranging, we get volume = weight / (density * 9.8) [m^3] Find the weight in [N], then you will know the volume in [m^3].


How much force is needed to accelerate a 3 kg mass at a rate of 4 m per second squared?

F = m A = (3 kg) (4 m/s2) = 12 kg-m/s2 = 12 newtons


What is the size and direction of the final velocity of the tow cars if a 0.4 kg toy train car moving forward t 3 ms collides with and sticks to 0.8 kg toy car that is traveling in the opposite way?

0.4 kg(3 m/s) + 0.8kg(-2 m/s) = 1.2 kg m/s -1.6 kg m/s = -0.4 kg m/s -0.4 kg m/s = 1.2 kg(v) = (-0.4 kg m/s)/(1.2 kg) = v = -0.33 m/s the cars are traveling at 0.33 m/s in the direction of the second car.


Hooke's law if a 3 kg mass stretches a spring 40 cm how far will a 5 kg mass stretch the spring?

The first step here is to find the spring constant. Use Hooke's law and the information given about the 3 kg mass: F=kx F=w3kg-mass=m3kg-massg=(3 kg)(9.8 m/s2) (3 kg)(9.8 m/s2)=(.40 m)k k=[(3 kg)(9.8 m/s2)/(.40 m)] Now plug that in (I don't have a calculator handy, and some of the units and numbers there will cancel, so I didn't bother to calculate it out) to Hooke's law for the 5 kg mass: F=kx F=w5kg-mass=m3kg-massg=(5 kg)(9.8 m/s2) (5 kg)(9.8 m/s2)=kx (5 kg)(9.8 m/s2)=[(3 kg)(9.8 m/s2)/(.40 m)]x x=2/3 m The 5 kg mass would stretch the spring two thirds of a meter.


1 kg watt is equal to how many newtons?

I don't think there is any equivalency.... A watt isW = J/s = (N*m)/s = ((kg*(m/s^2))*m)/s = kg*(m^2))/(s^3)Therefore: W*kg = (kg^2)*((m^2)/(s^3)) which is not equal to N = kg*(m/s^2)I guess the closest answer would be :1 kg*W = (1 kg*m/s) N or1 kg*W = (1 N*s) N


What is the density of heating oil?

It depends on the temperature. For 0 degrees Celsius it is 899.0 kg/m^3. For 20 degrees it is 888.1 kg/m^3. For 40 degrees it is 876.0 kg/m^3. For 60 degrees it is 863.9 kg/m^3. For 80 degrees it is 852.0 kg/m^3. For 100 degrees it is 840.0 kg/m^3. For 120 degrees it is 828.9 kg/m^3. For 140 degrees it is 816.8 kg/m^3. For 150 degrees it is 810.3 kg/m^3.


Dry air has a density of 1.29kgm 3 What would be the volume of a metric ton of air?

(1000 kg ) / (1.29 kg/m^3) = 775 m^3


What is less denser Saturn or water?

Saturn is less dense...Water is 1000 kg/m^3 and Saturn is 700 kg/m^3


Which is heavier brass or copper?

density of copper = 8930 kg/m^3 & density of brass = 8700 kg/m^3 copper is heavier


Density of astm a36?

About 7848 kg/m3