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How much force is needed to accelerate a 3 kg mass at a rate of 4 m per second squared?
F = m A = (3 kg) (4 m/s2) = 12 kg-m/s2 = 12 newtons
Hooke's law if a 3 kg mass stretches a spring 40 cm how far will a 5 kg mass stretch the spring?
The first step here is to find the spring constant. Use Hooke's law and the information given about the 3 kg mass: F=kx F=w3kg-mass=m3kg-massg=(3 kg)(9.8 m/s2) (3 kg)(9.8 m/s2)=(.40 m)k k=[(3 kg)(9.8 m/s2)/(.40 m)] Now plug that in (I don't have a calculator handy, and some of the units and numbers there will cancel, so I didn't bother to calculate it out) to Hooke's law for the 5 kg mass: F=kx F=w5kg-mass=m3kg-massg=(5 kg)(9.8 m/s2) (5 kg)(9.8 m/s2)=kx (5 kg)(9.8 m/s2)=[(3 kg)(9.8 m/s2)/(.40 m)]x x=2/3 m The 5 kg mass would stretch the spring two thirds of a meter.
What equals kg divided by m cubed?
It mass mass per unit volume which is unit of density in (kg/m^3) Hope it helped M. Arsalan
Does silver or lead have a greater density?
With a temperature of T = 293 K. Lead: 11.3 103 kg m-3 Silver: 10.50 103 kg m-3
How do you convert 1m3 to kg?
To convert cubic meters (m^3) to kilograms (kg), you need to know the density of the substance in question. The formula for this conversion is: mass (kg) = volume (m^3) x density (kg/m^3). So, if you have the density of the substance, you can multiply the volume in cubic meters by the density to get the mass in kilograms.
