F = m A = (3 kg) (4 m/s2) = 12 kg-m/s2 = 12 newtons
The first step here is to find the spring constant. Use Hooke's law and the information given about the 3 kg mass: F=kx F=w3kg-mass=m3kg-massg=(3 kg)(9.8 m/s2) (3 kg)(9.8 m/s2)=(.40 m)k k=[(3 kg)(9.8 m/s2)/(.40 m)] Now plug that in (I don't have a calculator handy, and some of the units and numbers there will cancel, so I didn't bother to calculate it out) to Hooke's law for the 5 kg mass: F=kx F=w5kg-mass=m3kg-massg=(5 kg)(9.8 m/s2) (5 kg)(9.8 m/s2)=kx (5 kg)(9.8 m/s2)=[(3 kg)(9.8 m/s2)/(.40 m)]x x=2/3 m The 5 kg mass would stretch the spring two thirds of a meter.
It mass mass per unit volume which is unit of density in (kg/m^3) Hope it helped M. Arsalan
With a temperature of T = 293 K. Lead: 11.3 103 kg m-3 Silver: 10.50 103 kg m-3
To convert cubic meters (m^3) to kilograms (kg), you need to know the density of the substance in question. The formula for this conversion is: mass (kg) = volume (m^3) x density (kg/m^3). So, if you have the density of the substance, you can multiply the volume in cubic meters by the density to get the mass in kilograms.
Yes engine oil has density but the temperature varies. For 0 degrees Celsius it is 899.0 kg/m^3. For 20 degrees it is 888.1 kg/m^3. For 40 degrees it is 876.0 kg/m^3. For 60 degrees it is 863.9 kg/m^3. For 80 degrees it is 852.0 kg/m^3. For 100 degrees it is 840.0 kg/m^3. For 120 degrees it is 828.9 kg/m^3. For 140 degrees it is 816.8 kg/m^3. For 150 degrees it is 810.3 kg/m^3.
From the Steam Tables I get the following: T v sub f d ( kg / m^3 ] 15.0 C 0.001001 m^3/ kg 999.0 kg / m^3 20.0 C 0.001002 m^3/ kg 998.0 kg/ m^3 25.0 C 0.001003 m^3 / kg 1001 kg / L^3 30.0 C 0 .001004 m^3 / kg 996.0 kg/m^3 -------------------- Search also NISTIR 6969, table 9.8 (it's free on Internet) or a density calculator.
mass [kg] = volume [m^3] * density [kg / m^3] From Newton's 2nd law of motion, weight [N] = mass [kg] * 9.8 [m/s^2] = volume [m^3] * density [kg / m^3] * 9.8 [m/s^2]. Rearranging, we get volume = weight / (density * 9.8) [m^3] Find the weight in [N], then you will know the volume in [m^3].
F = m A = (3 kg) (4 m/s2) = 12 kg-m/s2 = 12 newtons
The first step here is to find the spring constant. Use Hooke's law and the information given about the 3 kg mass: F=kx F=w3kg-mass=m3kg-massg=(3 kg)(9.8 m/s2) (3 kg)(9.8 m/s2)=(.40 m)k k=[(3 kg)(9.8 m/s2)/(.40 m)] Now plug that in (I don't have a calculator handy, and some of the units and numbers there will cancel, so I didn't bother to calculate it out) to Hooke's law for the 5 kg mass: F=kx F=w5kg-mass=m3kg-massg=(5 kg)(9.8 m/s2) (5 kg)(9.8 m/s2)=kx (5 kg)(9.8 m/s2)=[(3 kg)(9.8 m/s2)/(.40 m)]x x=2/3 m The 5 kg mass would stretch the spring two thirds of a meter.
Lead has a density of approximately 11,343 kg/m^3 while petrol has a density of about 730 kg/m^3. To find the mass of lead that has the same volume as 1600 kg of petrol, we can use the formula: Mass = Volume x Density. So, the mass of lead would be (1600 kg x 730 kg/m^3) / 11,343 kg/m^3 = approximately 103 kg.
(1000 kg ) / (1.29 kg/m^3) = 775 m^3
Saturn is less dense...Water is 1000 kg/m^3 and Saturn is 700 kg/m^3
density of copper = 8930 kg/m^3 & density of brass = 8700 kg/m^3 copper is heavier
Density is calculated by dividing the mass of a substance by its volume. In this case, the density would be 45 kg / 43 m^3 = 1.05 kg/m^3.
The density of lead is approximately 11,340 kg/m^3. To find the mass of a 10.0 m^3 cube of lead, you would multiply the volume (10.0 m^3) by the density (11,340 kg/m^3), which equals 113,400 kg.
About 7848 kg/m3