0
Hooke's law if a 3 kg mass stretches a spring 40 cm how far will a 5 kg mass stretch the spring?
The first step here is to find the spring constant. Use Hooke's law and the information given about the 3 kg mass:
F=kx
F=w3kg-mass=m3kg-massg=(3 kg)(9.8 m/s2)
(3 kg)(9.8 m/s2)=(.40 m)k
k=[(3 kg)(9.8 m/s2)/(.40 m)]
Now plug that in (I don't have a calculator handy, and some of the units and numbers there will cancel, so I didn't bother to calculate it out) to Hooke's law for the 5 kg mass:
F=kx
F=w5kg-mass=m3kg-massg=(5 kg)(9.8 m/s2)
(5 kg)(9.8 m/s2)=kx
(5 kg)(9.8 m/s2)=[(3 kg)(9.8 m/s2)/(.40 m)]x
x=2/3 m
The 5 kg mass would stretch the spring two thirds of a meter.
What else can I help you with?
How much mass would you need to stretch the spring 5.5cm?
To determine the mass required to stretch a spring 5.5 cm, you would use Hooke's Law, which states that the force exerted by a spring is proportional to its displacement. The formula is ( F = kx ), where ( F ) is the force (in newtons), ( k ) is the spring constant (in N/m), and ( x ) is the displacement (in meters). You would convert 5.5 cm to meters (0.055 m) and then rearrange the formula to find the mass ( m = \frac{F}{g} ), where ( g ) is the acceleration due to gravity (approximately 9.81 m/s²). Without the spring constant ( k ), the exact mass cannot be calculated.
Can you measure mass using spring balance?
Yes
How do you measure the mass of a cow?
Put her on a truck and have the truck weighed on a balance scale (NOT a spring scale). From this you can get true mass.
What unit of measure is spring scale to?
Mass (Newtons(N)) and Weight (grams(g))
Can the speed and frequency of the waves in a spring be changed?
All violinists believe so. The springs (= violin string) properties of frequency and timbre can be altered by the pressure of the bow against the string. Even in a simple coiled spring, you'll find the period of the pluck waves will change as the spring is elongated. But the purist will point out (correctly) that it is now a different spring. My favourite demonstration is of a rubber band about 200 mm long, with a mass at the lower end. This spring+mass apparatus has at least three resonant periods! First is that of a simple pendulum. Second is that of a torsional resonance (much slower). Third is that of the vertical oscillation of a spring-mass system.
Suggest suitable Experiments to find spring constant of a helical spring?
Connect a mass to the bottom of the spring. (depending on the spring size, the mass will vary, the larger the spring the greater the mass u can use) Suppose you use a 100 g mass on a spring, measure the amount by which it stretches and record the data. Use hooke law to figure out the constant of the spring. K = m.g/x m = mass, g =gravity, x = stretch
A mass of 4 kg stretches a spring 6 cm what is the mass of an object which streches the spring 9 cm?
Using Hooke's Law, we can set up a proportion to solve for the mass of the object stretching the spring 9 cm. Since the force required to stretch a spring is directly proportional to the distance stretched, an object with a mass of 6 kg would stretch it to 9 cm.
A 75 kg mass attached to a vertical spring stretches the spring 30 m what is the spring constant?
24.5 newtons per meter
A mass of 1.7kg caused a vertical spring to scretch 6m what's the spring constant?
A mass of 1.7kg caused a vertical spring to stretch 6m so the spring constant is 2.78.
What mass would be needed to stretch the spring to a length of 60 cm?
1,500 grams2,500 grams500 grams2,000 grams
Predict how many centimeters the spring will stretch if a total mass of 700 grams were attached?
To predict how many centimeters the spring will stretch, we need to know the spring constant in N/cm and apply Hooke's Law. Hooke's Law states that the force exerted by a spring is directly proportional to its extension. By knowing the spring constant and the total mass attached, we can calculate the stretch.
Explain why the spring stretches while the system is rotating when performing a lab experiment on uniform circular motion?
As the system rotates, the mass is moved in a circle which means that there is a net force acting on it and is directed towards the center. That force is provided by the spring which has to be streched in order to provide the force needed.
What do a pan-balance and the spring scale each measure?
A pan balance measures mass by comparing an unknown mass to a known mass using weights on a balancing scale. A spring scale measures force by the amount of stretch or compression in a spring when a force is applied to it.
What does a spring scale messure?
A spring scale measures the force exerted on an object. When an object is hung from the scale, the scale's spring stretches or compresses, and the amount of deformation is used to determine the force exerted by the object.
How much will the spring be stretched 25kg of 4500Nm?
To calculate the spring stretch, you need to use Hooke's Law formula which states F = kx, where F is force, k is the spring constant, and x is the displacement/stretch of the spring. Rearranging the formula to solve for x, you get x = F/k. Given force (4500 N) and mass (25 kg), you can calculate the force as F = m*g, where m is the mass and g is the acceleration due to gravity (9.81 m/s^2). Then, you can calculate the spring constant using Hooke's Law formula with the given force and stretch. Subsequently, use this spring constant to determine the stretch of the spring by rearranging the Hooke's Law formula.
Does gaining muscle mass affect the appearance of a tattoo?
If you gain muscle mass then it will stretch it. But if you gain a lot of muscle mass then it will stretch it and make it fade color. Depending on how much muscle mass you gain will depend on how much it stretches and fades. the tattoo should stretch to fit with your new size. however using steroids will cause the tattoo to stretch too far in one direction or another, thus permanently disfiguring it. whether it will fade i dont know. but the tattoo will resize with you skin (Assuming natural muscle growth).
How much mass would you need to stretch the spring 5.5cm?
To determine the mass required to stretch a spring 5.5 cm, you would use Hooke's Law, which states that the force exerted by a spring is proportional to its displacement. The formula is ( F = kx ), where ( F ) is the force (in newtons), ( k ) is the spring constant (in N/m), and ( x ) is the displacement (in meters). You would convert 5.5 cm to meters (0.055 m) and then rearrange the formula to find the mass ( m = \frac{F}{g} ), where ( g ) is the acceleration due to gravity (approximately 9.81 m/s²). Without the spring constant ( k ), the exact mass cannot be calculated.
