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3*2*4 = 24
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What does 2x plus 10 equals 9 plus 11-3x equal?
2x+10=9+11-3x2x+10=20-3x5x+10=205x=10x=2
What is the solution for 3x plus y equals 4 and x plus y equals 0?
3x + y = 4x + y = 0solve for yy = -3x +4y = -xsubstitute y = -x into y = -3x +4, so the result is: -x = -3x +4solve for x-1x = -3x +4+3x +3x2x = 4--------2x = 2then plug the x-value into one of the bolded equations and solve for y.I chosey = -xy = -(2)y = -2so the final answer is the ordered pair (2, -2)
How do you make the numbers 11-20 using four 4's?
11 = (42 - 4) - (4 / 4) 12 = (4 + 4) + (√4 + √4) 13 = (42 - 4) + (4 / 4) 14 = (4 + 4 + 4 + √4) 15 = (4 * 4) - (4 / 4) 16 = (4 + 4 + 4 + 4) 17 = (42 + √4) - (4 / 4) 18 = (42 + 4) - (4 - √4) 19 = (42 + 4) - (4 / 4) 20 = (4 * 4) + (√4 + √4)
How do you make the numbers 1-10 with four 4's using BODMAS?
Here is one set of solutions. The answers here are not unique. 1 = (4*4)/(4*4) 2 = 4/4 + 4/4 3 = (4+4+4)/4 4 = (4-4)*4 + 4 5 = (4*4 + 4) / 4 6 = 4 + (4+4)/4 7 = 4 + 4 - 4/4 8 = 4 + 4 + 4 - 4 9 = 4 + 4 + 4/4 10 = (44 - 4)/4
How do you get 4 by using four 4's?
3 simple solutions (there are more): (4-4)/4 + 4 = 4 4*(4-4)+ 4 = 4 4-((4-4)/4)) = 4
What is the answer -2x 48-3x-3x2x 6 3x?
the answer is 6
5x-16 equals 3x?
5x - 16 = 3x2x - 16 = 02x = 16x = 8
What does 2x plus 10 equals 9 plus 11-3x equal?
2x+10=9+11-3x2x+10=20-3x5x+10=205x=10x=2
What is the solution for 3x plus y equals 4 and x plus y equals 0?
3x + y = 4x + y = 0solve for yy = -3x +4y = -xsubstitute y = -x into y = -3x +4, so the result is: -x = -3x +4solve for x-1x = -3x +4+3x +3x2x = 4--------2x = 2then plug the x-value into one of the bolded equations and solve for y.I chosey = -xy = -(2)y = -2so the final answer is the ordered pair (2, -2)
How do you solve the equation 5x-93x 11 and are these simultanous equation if there are no answers on the end of each equation?
I assume you have : 5x - 9 = 3x + 11This is a single algebraic expression.Subtract 3x from both sides.5x - 9 - 3x = 3x + 11 - 3x2x - 9 = 11Add 9 to both sides :2x - 9 + 9 = 11 + 92x = 20x = 10
How do you get 1-50 with only the numbers 1 2 3 and 4?
1 2 3 4 4+1 4+2 4+3 4+4 4+4+1 4+4+2 4+4+3 4+4+4 4+4+4+1 4+4+4+2 4+4+4+3 4+4+4+4 4+4+4+4+1 4+4+4+4+2 4+4+4+4+3 4+4+4+4+4 4+4+4+4+4+1 4+4+4+4+4+2 4+4+4+4+4+3 4+4+4+4+4+4 4+4+4+4+4+4+1 4+4+4+4+4+4+2 4+4+4+4+4+4+3 4+4+4+4+4+4+4 4+4+4+4+4+4+4+1 4+4+4+4+4+4+4+2 4+4+4+4+4+4+4+3 4+4+4+4+4+4+4+4 4+4+4+4+4+4+4+4+1 4+4+4+4+4+4+4+4+2 4+4+4+4+4+4+4+4+3 4+4+4+4+4+4+4+4+4 4+4+4+4+4+4+4+4+4+1 4+4+4+4+4+4+4+4+4+2 4+4+4+4+4+4+4+4+4+3 4+4+4+4+4+4+4+4+4+4 4+4+4+4+4+4+4+4+4+4+1 4+4+4+4+4+4+4+4+4+4+2 4+4+4+4+4+4+4+4+4+4+3 4+4+4+4+4+4+4+4+4+4+4 4+4+4+4+4+4+4+4+4+4+4+1 4+4+4+4+4+4+4+4+4+4+4+2 4+4+4+4+4+4+4+4+4+4+4+3 4+4+4+4+4+4+4+4+4+4+4+4 4+4+4+4+4+4+4+4+4+4+4+4+1 4+4+4+4+4+4+4+4+4+4+4+4+2 I hope this is the answer you search for! (because it took some time!)
How can you make numbers 1-25 out of fours?
26
Using the number 4 four times can you make 1-100?
1 = 4*4/(4*4) 2 = 4/4+4/4 3 = (4+4+4)/4 4 = (4-4)/4+4 5 = 4^(4-4)+4 6 = (4+4)/4+4 7 = 4+4-4/4 8 = 4+4+4-4 9 = 4/4+4+4 10 = (4*4+4!)/4 11 = (4+4!)/4+4 12 = (4-4/4)*4 13 = (4+4!+4!)/4 14 = 4!/4+4+4 15 = 4*4-4/4 16 = 4*4+4-4 17 = 4*4+4/4 18 = (4*4!-4!)/4 19 = 4!-(4+4/4) 20 = (4/4+4)*4 21 = 4!+4/4-4 22 = 4!-(4+4)/4 23 = 4!-4^(4-4) 24 = 4*4+4+4 25 = 4!+(4/4)^4 26 = 4!+4!/4-4 27 = 4!+4-4/4 28 = (4+4)*4-4 29 = 4/4+4!+4 30 = (4*4!+4!)/4 31 = (4+4!)/4+4! 32 = 4^4/(4+4) 33 = (4-.4)/.4+4! 34 = 4!/4+4+4! 35 = (4.4/.4)+4! 36 = (4+4)*4+4 37 = 4/.4+4+4! 38 = 44-4!/4 39 = (4*4-.4)/.4 40 = (4^4/4)-4! 41 = (4*4+.4)/.4 42 = 4!+4!-4!/4 43 = 44-4/4 44 = 4*4+4+4! 45 = (4!/4)!/(4*4) 46 = (4!-4)/.4 - 4 47 = 4!+4!-4/4 48 = (4*4-4)*4 49 = 4!+4!+4/4 50 = (4*4+4)/.4 51 = 4!/.4-4/.4 52 = 44+4+4 53 = 44+4/.4 54 = (4!/4)^4/4! 55 = (4!-.4)/.4-4 56 = 4!+4!+4+4 57 = 4/.4+4!+4! 58 = (4^4-4!)/4 59 = 4!/.4-4/4 60 = 4*4*4-4 61 = 4!/.4+4/4 62 = (4!+.4+.4)/.4 63 = (4^4-4)/4 64 = 4^(4-4/4) 65 = 4^4+4/4 66 = (4+4!)/.4-4 67 = (4+4!)/.4+4 68 = 4*4*4+4 69 = (4+4!-.4)/.4 70 = (4^4+4!)/4 71 = (4!+4.4)/.4 72 = (4-4/4)*4! 73 = (.4√4+.4)/.4 74 = (4+4!)/.4+4 75 = (4!/4+4!)/.4 76 = (4!-4)*4-4 77 = (4!-.4)/.4+4! 78 = (4!*.4+4!)/.4 79 = (.4√4-.4)/.4 80 = (4*4+4)*4 81 = (4/4-4)^4 82 = 4!/.4+4!+4 83 = (4!-.4)/.4+4! 84 = (4!-4)*4+4 85 = (4/.4+4!)/.4 86 = (4-.4)*4!-.4 87 = 4!*4-4/.4 88 = 4^4/4+4! 89 90 = (4!/4)!/(4+4) 91 92 = (4!-4/4)*4 93 94 = (4+4!)/.4 + 4! 95 = 4!*4-4/4 96 = 4!*4+4-4 97 = 4!*4+4/4 98 = (4!+.4)*4+.4 99 = (4!+4!-4)/.4 100 = 4*4/(.4*.4)
How do you get 27 only using 4 fours?
(4+4+4+4+4+4+4+4+4+4+4+4+4+4+4+4+4+4+4+4+4+4+4+4+4+4+4) ÷ 4 = 27
what is 4+4+4+4+4+4+4+4+4+4=what?
4 +4+4+4+4+4+4+4+4=40
How do you get 13 using 4 fours?
1 = 44 / 44 2 = 4 * 4 / (4 + 4) 3 = (4 + 4 + 4) / 4 4 = 4 + (4 * (4 - 4)) 5 = (4 + (4 * 4)) / 4 6 = 4 + ((4 + 4) / 4) 7 = (44 / 4) - 4 8 = 4 + 4 + 4 - 4 9 = 4 + 4 + (4 / 4) 10 = (44 - 4) / 4 11 = (4 / 4) + (4 / .4) 12 = (4 + 44) / 4 13 = 4 + ((4 - .4) / .4) 14 = (4 * (4 - .4)) - .4 15 = 4 + (44 / 4) 16 = (44 - 4) * .4 17 = (4 * 4) + (4 / 4) 18 = (44 * .4) + .4 19 = (4 + 4 - .4) / .4 20 = 4 * (4 + (4 / 4))
How do you find at least 6 math equations using only 6 fours to make it equal any prime number in between 1-100?
The primes required are: 2 = (4+4)/4 3 = (4+4+4)/4 5 = (4+4+4+4+4)/4 7 = (4*4+4+4+4)/4 11 = (4(4*4-4)-4)/4 13 = (4*(4*4-4)+4)/4 17 = (4*4*4+4)/4 19 = (4*(4*4+4)-4)/4 23 = (4*(4*4+4+4)-4)/4 29 = (4*(4*4+4+4+4)+4)/4 31 = (4*4*(4+4)-4)/4 37 = (4*4*(4+4)+4*4+4)/4 41 = (4^4-4*(4*4)+4)/4 43 = (4^4-4(4*4+4+4))/4 47 = (4^4-4*4*4-4)/4 The remainder are left as an exercise. It should be noted that most of these are impossible to express with only six fours without either defining new operators or allowing for facetious, unmathematical cheats such as allowing 44 to be used.
