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The primes required are:

2 = (4+4)/4

3 = (4+4+4)/4

5 = (4+4+4+4+4)/4

7 = (4*4+4+4+4)/4

11 = (4(4*4-4)-4)/4

13 = (4*(4*4-4)+4)/4

17 = (4*4*4+4)/4

19 = (4*(4*4+4)-4)/4

23 = (4*(4*4+4+4)-4)/4

29 = (4*(4*4+4+4+4)+4)/4

31 = (4*4*(4+4)-4)/4

37 = (4*4*(4+4)+4*4+4)/4

41 = (4^4-4*(4*4)+4)/4

43 = (4^4-4(4*4+4+4))/4

47 = (4^4-4*4*4-4)/4

The remainder are left as an exercise. It should be noted that most of these are impossible to express with only six fours without either defining new operators or allowing for facetious, unmathematical cheats such as allowing 44 to be used.

Q: How do you find at least 6 math equations using only 6 fours to make it equal any prime number in between 1-100?

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4000 = 40 = 3960

To achieve the number 77 with four fours, the solution is as follows: sqrt(4/.4)4 - 4 Instead of the second four being equal to four tenths, place a dot over the top to indicate it being equal to four ninths.

(4x4+4) / 4=5

8. The function of "times" is to add that number to itself by the second number. So the 4x2 means that you add two fours together. 4x3=12...4+4+4. See how it works?

A solution to the four fours problem for the number 33 is: 33 = (4-.4)/.4+4!

Related questions

4000 = 40 = 3960

4*4+4/4 = 17

2.5x4

To achieve the number 77 with four fours, the solution is as follows: sqrt(4/.4)4 - 4 Instead of the second four being equal to four tenths, place a dot over the top to indicate it being equal to four ninths.

four fours equals 24 not 23. or if u meant four 4ths, then it's 256.

(4x4+4) / 4=5

A 6 should be placed between the fours.

{4! - sqrt(4)}/.4

Three fours (12) is not equal to nine twelves (108). However, three over four (3/4) is equal to nine over twelve (9/12) which are known as equivalent fractions to each other.

8465*65

4/4 + 4 × 4/4

4*4+4/4 = 17