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P is not 1, 2, 3 or 6.

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8y ago
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Q: What is the answer to P not a factor of 6?
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6(p - 18)


What is the factor of 6m pm?

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You have to use the quadratic formula: p=(6±√(36+72))/2 p=(6±√108)/2 p=3±3√3


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Yes it is. The proof is as follows:We prove the statement by contradiction i.e. Assume that sqrt(6) is a rational number.Then there exist positive integers p and q with gcd(p,q) = 1 such that p/q = sqrt(6).Square both sides: p^2 / q^2 = 6,p^2 = 6q^2.Now as 2 is a divisor of the right-hand side (RHS), it implies that 2 is also a divisor of the left-hand side (LHS).This is only possible if 2 is a factor of p.Let p =2k. Then k is a positive integer as well.Thus, 4k^2 = 6q^2,2k^2 = 3q^2.As 2 is a factor of the LHS, 2 is also a factor of the RHS.But this is only possible if 2 is a factor of q.=> gcd(p,q) >= 2. Contradiction!Thus sqrt(6) is irrational.yes it is


What binomial is a factor of this trinomial x2 plus 13x plus 4?

x2 + 13x + 4 = (x + 6½ + √38¼)(x + 6½ - √38¼). To find this, we need to find p and q, where p + q = 13, pq = 4. 4 = 42¼ - 38¼ = (6½ + √38¼)(6½ - √38¼); thus, p = (6½ + √38¼), q = (6½ - √38¼).


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How do you read this 6 is a factor of 54 or 54 is a factor of 6?

6 is a factor of 54.


What is the algebraic expression for p divided by 6?

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