Q: What is factor theorem?

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The remainder is not zero so y-3 is not a factor of y^4+2y^2-4

we can use direct substitution. do this we must take the opposite of the constant in the factor that we want to test. -1*(1)=-1 now we simply take f(-1). =-1^3-(-2)^2-8(-1)-5 =-1-4+8-5 =-2 since we got -2 in the end (x+1) is not a factor of this polynomial. According to factor theorem it can only be a factor is the remainder is 0

Norton's theorem is the current equivalent of Thevenin's theorem.

You cannot solve a theorem: you can prove the theorem or you can solve a question based on the remainder theorem.

That is a theorem.A theorem.

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In algebra, the factor theorem is a theorem linking factors and zeros of a polynomial. It is a special case of the polynomial remainder theorem.The factor theorem states that a polynomial has a factor if and only if

In algebra, the factor theorem is a theorem linking factors and zeros of a polynomial. It is a special case of the polynomial remainder theorem.The factor theorem states that a polynomial has a factor if and only if

you

The remainder is not zero so y-3 is not a factor of y^4+2y^2-4

when simplifying fractions

Suppose p(x) is a polynomial in x. Then p(a) = 0 if and only if (x-a) is a factor of p(x).

Never forget to factor in the "kids are stupid" theorem when trying to figure out why kids do anything.

In algebra, the rational root theorem (or rational root test, rational zero theorem or rational zero test) states a constraint on rational solutions (or roots) of a polynomialequationwith integer coefficients.If a0 and an are nonzero, then each rational solution x, when written as a fraction x = p/q in lowest terms (i.e., the greatest common divisor of p and q is 1), satisfiesp is an integer factor of the constant term a0, andq is an integer factor of the leading coefficient an.The rational root theorem is a special case (for a single linear factor) of Gauss's lemmaon the factorization of polynomials. The integral root theorem is a special case of the rational root theorem if the leading coefficient an = 1.

we can use direct substitution. do this we must take the opposite of the constant in the factor that we want to test. -1*(1)=-1 now we simply take f(-1). =-1^3-(-2)^2-8(-1)-5 =-1-4+8-5 =-2 since we got -2 in the end (x+1) is not a factor of this polynomial. According to factor theorem it can only be a factor is the remainder is 0

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The fundamental theorem of arithmetic says any integer can be factored into a unique product of primes. The is the prime factored form.

Norton's theorem is the current equivalent of Thevenin's theorem.