16 - 4 = 12
You use the Pythagorian Theorum, a2 + b2 = c2, where c is the length of the hypotenuse. If a2 + b2 = c2 then a2 = c2 - b2. Let's say that b is the side opposite Θ. Since sinΘ = b/c, a2 = 5 - 4 = 1, so a = 1. Since tanΘ = b/a, tanΘ = 2.
a2+ b2= c2 axa=____ ____ bxb=____ +____=c c2 c=__.__
a2+b2=c2 22+42=c2 4+16=c2 20=c2 c=square root of 20
a2+b2+c2=x2+y2+z2 divide each side by 2 (a2+b2+c2)/2=(x2+y2+z2)/2 a+b+c=x+y+z
(a+b-c)2 = a2 + b2 +c2 +2ab - 2bc - 2ac
a2 + b2 + c2 - ab - bc - ca = 0 => 2a2 + 2b2 + 2c2 - 2ab - 2bc - 2ca = 0 Rearranging, a2 - 2ab + b2 + b2 - 2bc + c2 + c2 - 2ca + a2 = 0 => (a2 - 2ab + b2) + (b2 - 2bc + c2) + (c2 - 2ca + a2) = 0 or (a - b)2 + (b - c)2 + (c - a)2 = 0 so a - b = 0, b - c = 0 and c - a = 0 (since each square is >=0) that is, a = b = c
You use the Pythagorian Theorum, a2 + b2 = c2, where c is the length of the hypotenuse. If a2 + b2 = c2 then a2 = c2 - b2. Let's say that b is the side opposite Θ. Since sinΘ = b/c, a2 = 5 - 4 = 1, so a = 1. Since tanΘ = b/a, tanΘ = 2.
use Pythagorean theorem (A2 + B2 = C2).A is a side touching the right angle, B is the other side and C is the hypotenuse. example: A = 3, B = 4, C = ?, A2 + B2 = C2, 32 + 42 = c2, 9 + 16 = c2, 25 = c2 5 = c
a2+ b2= c2 axa=____ ____ bxb=____ +____=c c2 c=__.__
a2+b2=c2 22+42=c2 4+16=c2 20=c2 c=square root of 20
The pythagorean theory or pythagorean theorem is a formula to find the leg or the hypotenuse for a right triangle. There are three parts to a triangle, The legs(A2) and (B2). The hypotenuse (C2). The hypotenuse is always the longest side of the triangle it is always adjacent to the 900 angle of the right triangle. The actual pythagorean theorem is A2 + B2 = C2. Example: A=2 B= 4 C=? A2 + B2 =C2 22 + 42 =C2 4 + 16= C2 20=C2 Now you find the square root for the two numbers you just added 4.4 = C
a3 + b3 + c3 + 2(a2)b + 2(b2)c + 2(a2)c + 2ab2 + 2(c2)b +abc
The length of a hypotenuse C can be calculated by squaring 'legs' A and B of a given right triangle. Where A2 + B2 = C2 Such that 22 + 32 = C2 22 +32 = C2 4 + 9 = C2 13 = C2 √(13) = C
For a triangle with sides a, b anc c, where A is the angle opposite side a, B is the angle opposite side b, etc.:cos A = ( b2 + c2 - a2 ) / ( 2 bc )cos B = ( a2 + c2 - b2 ) / ( 2 ac )cos C = ( a2 + b2 - c2 ) / ( 2 ab )These are just rearrangements of the ordinary cosine rule:a2 = b2 + c2 - 2 bc cos A
a2+b2+c2=x2+y2+z2 divide each side by 2 (a2+b2+c2)/2=(x2+y2+z2)/2 a+b+c=x+y+z
(a+b-c)2 = a2 + b2 +c2 +2ab - 2bc - 2ac
C = sqrt(C2) C2 = A2 + B2 - 2 A B cos(AB)