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a2 + b2 + c2 - ab - bc - ca = 0

=> 2a2 + 2b2 + 2c2 - 2ab - 2bc - 2ca = 0

Rearranging,

a2 - 2ab + b2 + b2 - 2bc + c2 + c2 - 2ca + a2 = 0

=> (a2 - 2ab + b2) + (b2 - 2bc + c2) + (c2 - 2ca + a2) = 0

or (a - b)2 + (b - c)2 + (c - a)2 = 0

so a - b = 0, b - c = 0 and c - a = 0 (since each square is >=0)

that is, a = b = c

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15y ago

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