There are 4 tens in 40. If you multiply 82 by ten four times, you'll get the answer.
820 + 820 + 820 + 820 = 3280
82 x 40 = 3280
if 29 x 6 = 174 and 29x 10 = 290 then the answer to 29 x 16 is made by adding up the answers to 29x6 and 29x10
5x5, 5x50, 5x500
The product of 10 tens is 100
37*4 = 148 which is 14 tens and 8 units
You cannot. You have to also use multiplication by 2 or 4 (or division by 5 or 25), or addition.
Consider the example 234 x 26.When multiplying out, you do the ones digit first, then the tens digit:ones: 234 x 6 = 1404tens: 234 x 2 = 468and then add the results together.However, the value of the tens digit is the_digit x 10. So in this example, the tens digit is not worth two (2) but twenty (20 = 2 x 10). Thus the correct value of multiplying by the tens digit is:234 x 2 x 10 = 468 x 10 = 4680(The correct sum is: 234 x 26 = 1406 + 4680 = 6084)So when multiplying by the tens digit there will be a zero (0) on the end.Similarly when multiplying by a hundreds digit there will be two zeros (00) on the end.To avoid forgetting to do this, the zero(s) is(are) normally written in first before doing the multiplication by the tens (hundreds, etc) digit.
14 and 8 units
The answer will depend on the order in which you do partial products. It is quite common in the UK for the first partial product to be the two digits in the tens' place and so that is often the largest. This ties in with the method for multiplying two binomials when they move on to algebra.
37x7=148 therefore 14x10+8=148 is regrouped
This is because we count in tens so that the place value of a digit is ten times the place value of the digit to its right.
This is because we count in tens so that the place value of a digit is ten times the place value of the digit to its right.
The 3 is in the tens column, so it is thirty;Multiplying this by 1000 gives thirty thousand.