0
What is the last but one digit in the product of the first 75 even natural numbers?
To find the last but one digit in the product of the first 75 even natural numbers, we need to consider the units digit of each number. Since we are multiplying even numbers, the product will end in 0. Therefore, the last but one digit (tens digit) will depend on the multiplication of the tens digits of the numbers. The tens digit will be determined by the pattern of the tens digits of the even numbers being multiplied.
What else can I help you with?
What is the ones digit number in the product of the first 100 numbers?
Zero.
What proportion of the first 10000 natural numbers contain a 5?
271 of the first 1000 natural numbers contain at least one digit 5. That is 27.1 % of them.
How many three digits natural numbers are divisible by 4?
The first 3 digit natural number is 100: 100 ÷ 4 = 25 → first 3 digit natural number divisible by 4 is 4 × 25 The last 3 digit natural number is 999: 999 ÷ 4 = 249 r 3 → last 3 digit natural number divisible by 4 is 4 × 249 → number of 3 digit natural numbers divisible by 4 is 249 - 25 + 1 = 225.
Explain why second partial product is always greater than the first partial priduct when you multiply two 2-digit numbers?
The product of two digit numbers is always greater than either.
What fraction of all 4 digits natural numbers have a product of their digits that is even?
To find the fraction of 4-digit natural numbers with a product of their digits that is even, we first need to determine the total number of 4-digit natural numbers. There are 9000 such numbers (from 1000 to 9999). Next, we consider the conditions for the product of digits to be even. For a number to have an even product of digits, at least one of the digits must be even. There are 5 even digits (0, 2, 4, 6, 8) and 5 odd digits (1, 3, 5, 7, 9). Therefore, the fraction of 4-digit natural numbers with an even product of digits is 5/10 * 9/10 * 9/10 * 9/10 = 3645/9000 = 809/2000.
What is the last digit in the product of the first 20 odd natural numbers?
The last digit in the product of the first 20 odd natural numbers can be determined by looking at the pattern of the units digit in the multiplication of consecutive odd numbers. The units digit of the product of consecutive odd numbers alternates between 1 and 5. Since there are 10 odd numbers between 1 and 19, and 20 is also an odd number, the last digit in the product of the first 20 odd natural numbers is 5.
What is the last but one digit in the product of the first 10 even natural numbers?
It is 0.
What is the digit in the tens place in the product of the first 35 even natural numbers?
The first 35 even natural numbers are 2, 4, 6, ..., 70. The product of these numbers can be expressed as (2^{35} \times 35!). The presence of multiple factors of 10 (from the factors of 2 and 5 in (35!)) means that the product will end in at least one zero. Therefore, the digit in the tens place of this product is 0.
What fraction of all four digit natural numbers have a product of their digits that is even?
To find the fraction of four-digit natural numbers with an even product of their digits, we first note that a four-digit number ranges from 1000 to 9999, giving us a total of 9000 four-digit numbers. The product of the digits is even if at least one digit is even. The only case where the product is odd is if all four digits are odd. The odd digits are 1, 3, 5, 7, and 9, offering 5 choices for each digit. Thus, the total odd-digit combinations for four-digit numbers is (5^4 = 625). Therefore, the number of four-digit numbers with an even product is (9000 - 625 = 8375). The fraction is then ( \frac{8375}{9000} = \frac{335}{360} ), which simplifies to approximately ( \frac{67}{72} ).
What is the ones digit number in the product of the first 100 numbers?
Zero.
What is the unit's digits of the product of the first 21 prime numbers?
The unit's digit is 0. That is true for the product of the first n primes provided n>2.The unit's digit is 0. That is true for the product of the first n primes provided n>2.The unit's digit is 0. That is true for the product of the first n primes provided n>2.The unit's digit is 0. That is true for the product of the first n primes provided n>2.
What proportion of the first 10000 natural numbers contain a 5?
271 of the first 1000 natural numbers contain at least one digit 5. That is 27.1 % of them.
What is the product of the first five natural numbers?
Good question. 1+2+3+4+5=155=15 So the product of first five natural numbers is fifteen Natural numbers starts from one So we add first five natural numbers and get the right answer is fifteen
What one-digit number is the product of two consecutive prime numbers?
There are only two prime numbers that are consecutive numbers, 2 and 3. Their product is 2 x 3 = 6. The first prime numbers are 2, 3, 5, and 7 and the only two consecutive prime numbers whose product is a single digit are 2 and 3. (The next two consecutive prime numbers, 3 and 5, have a two-digit product.)
What two numbers make up a product?
In any two-digit multiplication sum, for example, 3 x 2 = 6, the first digit is called the multiplier, the second digit is called a multiplicand, and the third digit, the answer, is the product.
How many three digits natural numbers are divisible by 4?
The first 3 digit natural number is 100: 100 ÷ 4 = 25 → first 3 digit natural number divisible by 4 is 4 × 25 The last 3 digit natural number is 999: 999 ÷ 4 = 249 r 3 → last 3 digit natural number divisible by 4 is 4 × 249 → number of 3 digit natural numbers divisible by 4 is 249 - 25 + 1 = 225.
Product of first five natural numbers?
120
