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Q: What is the last but one digit in the product of the first 75 even natural numbers?

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5.

It is 0.

Zero.

271 of the first 1000 natural numbers contain at least one digit 5. That is 27.1 % of them.

120

There are only two prime numbers that are consecutive numbers, 2 and 3. Their product is 2 x 3 = 6. The first prime numbers are 2, 3, 5, and 7 and the only two consecutive prime numbers whose product is a single digit are 2 and 3. (The next two consecutive prime numbers, 3 and 5, have a two-digit product.)

In any two-digit multiplication sum, for example, 3 x 2 = 6, the first digit is called the multiplier, the second digit is called a multiplicand, and the third digit, the answer, is the product.

The unit's digit is 0. That is true for the product of the first n primes provided n>2.The unit's digit is 0. That is true for the product of the first n primes provided n>2.The unit's digit is 0. That is true for the product of the first n primes provided n>2.The unit's digit is 0. That is true for the product of the first n primes provided n>2.

The first 3 digit natural number is 100: 100 ÷ 4 = 25 → first 3 digit natural number divisible by 4 is 4 × 25 The last 3 digit natural number is 999: 999 ÷ 4 = 249 r 3 → last 3 digit natural number divisible by 4 is 4 × 249 → number of 3 digit natural numbers divisible by 4 is 249 - 25 + 1 = 225.

3 digit numbers are lessthan 4 digit numbers

The product of two digit numbers is always greater than either.

10 because 10 is the first 2 digit number out of all numbers.

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