8
Zero.
271 of the first 1000 natural numbers contain at least one digit 5. That is 27.1 % of them.
The first 3 digit natural number is 100: 100 ÷ 4 = 25 → first 3 digit natural number divisible by 4 is 4 × 25 The last 3 digit natural number is 999: 999 ÷ 4 = 249 r 3 → last 3 digit natural number divisible by 4 is 4 × 249 → number of 3 digit natural numbers divisible by 4 is 249 - 25 + 1 = 225.
The product of two digit numbers is always greater than either.
Π5j=1 (j)=1x2x3x4x5=5!=120
5.
It is 0.
Zero.
Good question. 1+2+3+4+5=155=15 So the product of first five natural numbers is fifteen Natural numbers starts from one So we add first five natural numbers and get the right answer is fifteen
271 of the first 1000 natural numbers contain at least one digit 5. That is 27.1 % of them.
There are only two prime numbers that are consecutive numbers, 2 and 3. Their product is 2 x 3 = 6. The first prime numbers are 2, 3, 5, and 7 and the only two consecutive prime numbers whose product is a single digit are 2 and 3. (The next two consecutive prime numbers, 3 and 5, have a two-digit product.)
In any two-digit multiplication sum, for example, 3 x 2 = 6, the first digit is called the multiplier, the second digit is called a multiplicand, and the third digit, the answer, is the product.
120
The unit's digit is 0. That is true for the product of the first n primes provided n>2.The unit's digit is 0. That is true for the product of the first n primes provided n>2.The unit's digit is 0. That is true for the product of the first n primes provided n>2.The unit's digit is 0. That is true for the product of the first n primes provided n>2.
The first 3 digit natural number is 100: 100 ÷ 4 = 25 → first 3 digit natural number divisible by 4 is 4 × 25 The last 3 digit natural number is 999: 999 ÷ 4 = 249 r 3 → last 3 digit natural number divisible by 4 is 4 × 249 → number of 3 digit natural numbers divisible by 4 is 249 - 25 + 1 = 225.
The product of two digit numbers is always greater than either.
10 because 10 is the first 2 digit number out of all numbers.