A discriminant is based on the differences between roots of an equation. A linear equation, such as the onle in the question, has only one root and therefore cannot have a discriminant.
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The discriminant in the quadratic equation x2 + 11x + 121 = x + 96 is 0.Simplify the equation to the form Ax2 + Bx + C = 0 and you get x2 + 10x + 25 = 0. The discriminant is B2 - 4AC or 100 - (4)(1)(25) or 100 - 100 or 0.Not asked, but answered for completeness - since the discriminant is 0, there is one real solution, namely x = (-10 +/- 00.5) / 2 = -5
The discriminant is 900.
The discriminant of the equation ... (b2-4ac) = (225-160) ... is real and positive, so the roots are real and unequal.
One possibility is y = x^2 + 2.5
The discriminant of x^2 + 6 - 16 = discriminant of x^2 - 10 is 40.
Equation: x^2 +2kx +10x +k^2 +5 = 0 Using the discriminant: (2k +10)^2 -4*1*(k^2 +5) = 0 Solving the discriminant: k = -2
There are no solutions because the discriminant of this quadratic equation is less than zero
It's a quadratic expression which can't be factorized because its discriminant is less than zero.
2x2 + 10x - 3 The discriminant is defined as b2 - 4ac, so for this function b=10, a=2, and c=-3 So the discriminant is 100-4*2*-3 = 124
The answer to the mathematical equation of 10 plus 90 is 100.
The equation is -2y + 16 = 10