The discriminant in the quadratic equation x2 + 11x + 121 = x + 96 is 0.
Simplify the equation to the form Ax2 + Bx + C = 0 and you get x2 + 10x + 25 = 0. The discriminant is B2 - 4AC or 100 - (4)(1)(25) or 100 - 100 or 0.
Not asked, but answered for completeness - since the discriminant is 0, there is one real solution, namely x = (-10 +/- 00.5) / 2 = -5
This quadratic equation has no real roots because its discriminant is less than zero.
No. It is a quartic equation. The largest power of x in a quadratic equation must be 2.
NO,because in quadratic equation highest power of a variable is 2. e.x. 4x2-20x+10=0.
The discriminant is 25.
I suggest you use the quadratic formula. In this case, a = 1, b = 5, c = 3.
The discriminant is 0.
If you mean b^2 -4ac then it is the discriminant of a quadratic equation. If the discriminant equals 0 then the equation has 2 equal roots. If the discriminant is greater than 0 then the equation has 2 different roots. If the discriminant is less than 0 then it has no real roots.
It has no solutions because the discriminant of the quadratic equation is less than zero.
With difficulty because the discriminant of the quadratic equation is less than zero meaning it has no solutions
The discriminant is -27 and so there are no real roots.
This quadratic equation has no solutions because the discriminant is less than zero.
This quadratic equation has no solutions because its discriminant is less than zero.
The discriminant is -439 and so there are no real solutions.
The discriminant is -32.
There are no real solutions because the discriminant of the quadratic equation is less than zero.
This quadratic equation has no real roots because its discriminant is less than zero.
None because the discriminant of this quadratic equation is less than zero.